断言已排序的对象数组

Question

我正在使用 javascript 测试框架（mocha、chai 等）进行单元测试。如何使用名称断言我的对象数组？

我可以使用 localeCompare 成功地对此进行排序，但我在测试中没有得到我想要的结果。它只是 returns 1 或 -1.

这是我要排序的示例。

var Stuffs = [
     { name: "PWE", address: "1234567890" },
     { name: "NSA", address: "1234567890" },
     { name: "AVE", address: "1234567890" },
     { name: "QRE", address: "1234567890" },
  ]

我如何向 ["AVE", "NSA", "PWE", "QRE"] 断言？

Answer 1

要获得所需的数组，您可以使用：

Stuffs.map(({ name }) => name).sort();

Answer 2

使用柴

assert.deepInclude(Stuffs, {name: "AVE"});
assert.deepInclude(Stuffs, {name: "NSA"});
assert.deepInclude(Stuffs, {name: "QRE"});
assert.deepInclude(Stuffs, {name: "PWE"});

编辑：我可能误解了它的意思，如何断言数组具有这些值。

Answer 3

你也可以使用数组的reduce()方法然后sort()。

演示

var Stuffs = [{ name: "PWE", address: "1234567890" },
     { name: "NSA", address: "1234567890" },
     { name: "AVE", address: "1234567890" },
     { name: "QRE", address: "1234567890" }];
     
let sortedArr = Stuffs.reduce((r,{name})=>r.concat(name),[]).sort((a,b)=>a.localeCompare(b));

console.log(sortedArr);

Answer 4

首先，您需要一个排序数组来与之进行比较。由于 sort will modify the array it is called on. Using from 生成克隆，因此需要克隆原始数组（对此很浅），然后我们可以按字母顺序对新数组进行排序以获得所需的顺序。

const sortedStuffs = Array.from(stuffs).sort(({name: a}, {name: b}) => a.localeCompare(b));

最后使用 every，我们可以比较每个元素的名称以查看它们是否匹配。一旦失败，返回值将是 false

stuffs.every(({name}, i) => name === sortedStuffs[i].name);

完整的工作示例：

const stuffs = [
 {name: "PWE", address: "1234567890"},
 {name: "NSA", address: "1234567890"},
 {name: "AVE", address: "1234567890"},
 {name: "QRE", address: "1234567890"}
];

const sortedStuffs = Array.from(stuffs).sort(({name: a}, {name: b}) => a.localeCompare(b));

const isSorted = stuffs.every(({name}, i) => name === sortedStuffs[i].name);

console.log(isSorted);

断言已排序的对象数组

Assert sorted array of objects

javascript

sorting

assertions

chai

karma-mocha