如何在 tibbles 上取消 which.min

Question

/R-新人。我的 which.min 调用在我的数据框的一列上工作正常，但在加载 dplyr which.min 时不再工作。是因为 df 现在是 tibble 了吗？任何解决方法？

> which.min(Analytic_traces_raw[,1]) #********************WORKS FINE HERE**
[1] 1
> library(dplyr)

Attaching package: ‘dplyr’
The following objects are masked from ‘package:stats’:
    filter, lag
The following objects are masked from ‘package:base’:
    intersect, setdiff, setequal, union

> which.min(Analytic_traces_raw[,1]) #*********************NOW IT'S BROKEN**
Error in which.min(Analytic_traces_raw[, 1]) : 
  (list) object cannot be coerced to type 'double'

> head(Analytic_traces_raw[,1]) #**TYPE IS DBL, BUT TIBBLE TROUBLE**?
# A tibble: 6 x 1
  `t_Pur23Mar18_TP7-24`
                  <dbl>
1              0.000417
2              0.00375 
3              0.00708 
4              0.0104  
5              0.0138  
6              0.0171

Answer 1

类似这样的问题可以通过在命令前指定包名来解决，例如

raster::which.min(Analytic_traces_raw[,1])

（或者如果您实际使用的 which.min 与 dplyr 或 raster 中的不同，请替换包名称）。这是一个示例（尽管不是给出不同结果的示例）：

> data(iris)
> apply(iris, 2, raster::which.max)
$Sepal.Length
[1] 132

$Sepal.Width
[1] 16

$Petal.Length
[1] 119

$Petal.Width
[1] 101

$Species
integer(0)

> apply(iris, 2, base::which.max)
$Sepal.Length
[1] 132

$Sepal.Width
[1] 16

$Petal.Length
[1] 119

$Petal.Width
[1] 101

$Species
integer(0)

Answer 2

不是 which.min "broke" 而是 "broke" R 中的默认行为。通常，对于数据帧，Analytic_traces_raw[,1] 会降低维度并成为向量. tibbles 改变了这种行为，因此期望 "normal" 行为的 R 函数将会中断。尝试 Analytic_traces_raw[[1]]:

library(dplyr)
which.min(mtcars[,1])
[1] 15
> mtcars_tbl <- as_tibble(mtcars)
> which.min(mtcars_tbl[,1])
Error in which.min(mtcars_tbl[, 1]) : 
  (list) object cannot be coerced to type 'double'
> which.min(mtcars_tbl[[1]])
[1] 15

如何在 tibbles 上取消 which.min

How to un-break which.min on tibbles

r

dataframe

dplyr

tibble