Webflux 状态码无法更改

Question

所以我有一个 AuthenticationWebFilter 可以在有人像这样进行身份验证时添加触发器：

val builder : HttpSecurity.AuthorizeExchangeBuilder = http
            .addFilterAt(
                    CustomAuthenticationWebFilter(securityContextRepository),
                    SecurityWebFiltersOrder.AUTHENTICATION
            )
            .authorizeExchange().permitAll()

然后在 "CustomAuthenticationWebFilter" 中，我用一些逻辑更改了 statusCode，如下所示：

override fun filter(exchange: ServerWebExchange, chain: WebFilterChain): Mono<Void> {
    return super.filter(exchange, chain)
            .doOnSuccess {
                    exchange.response.statusCode = UNAUTHORIZED
                    return@doOnSuccess
             }

关键是，当我做一个请求时，流程会先到 WebFilter

AbstractServerHttpResponse#doCommit

然后状态变为 "COMMITTED" 当我调用

AbstractServerHttpResponse#setStatusCode

无法更改。

是否可以在提交前更改状态码？

build.gradle

compile('org.springframework.boot:spring-boot-starter-webflux') compile('org.springframework.security:spring-security-web') compile('org.springframework.security:spring-security-config')

Answer 1

好的，这几天测试了很多东西，我把"SecurityWebFiltersOrder"改成"SecurityWebFiltersOrder.AUTHORIZATION"

就解决了

Webflux 状态码无法更改

Webflux statuscode can not be changed

spring-security

kotlin

spring-webflux