如何获取 jwplayer 的 URL 源代码部分

Question

朋友们好...

如何获取 jwplayer 的 URL 源代码部分，我的意思是 mp4 部分，我在这里找到了我要找的东西 the source

我尝试使用它，但我做不好，抱歉我的英语不好，有人可以看看我下面的 php 代码....我想抓住 link http://localhost/srt/43534234/viral022018SD.MP4 and http://localhost/srt/43534234/viral022018HD.MP4 或 viral022018.html

里面的所有 mp4 URL

谢谢你希望有人帮助我...谢谢你

这是我的php代码

<?php
$html = file_get_contents('https://localhost/video/viral022018.html');
//$dom->loadHtml('', LIBXML_HTML_NOIMPLIED | LIBXML_HTML_NODEFDTD);
$dom = new DOMDocument();
$dom->loadHTML($html);

$xpath = new DOMXPath($dom);

$sources = [];
foreach ($xpath->query("//script[@type=\"text/javascript\"]") as $script) {
    if (stristr($script->nodeValue, 'playerInstance') !== false) {
        preg_match_all('#file: \"(.+)\"#', $script->nodeValue, $match);
        $sources = $match[1];
    }
}

print_r($sources);
?>

这是viral022018.html

<!DOCTYPE html>
<html>
<head>
<meta charset="UTF-8" />
<meta name="viewport" content="width=device-width, initial-scale=1, maximum-scale=1" />
<link href='https://fonts.googleapis.com/css?family=Hanuman' rel='stylesheet' type='text/css'>
<link href="https://fonts.googleapis.com/css?family=Scada" rel="stylesheet">
<link href="jwplayer-7.12.8/skins/prime.min2.css" rel="stylesheet" type="text/css" />
<script type="text/javascript" src="jwplayer-7.12.8/jwplayer.js"></script>
<script type="text/javascript">jwplayer.key="I9HOJrL1NmqruQ60as34wt34/23422dsdrwer==";</script>
</head>
<body>
<div id="picasa" class="picasa"></div>
<script type="text/javascript">
    var playerInstance = jwplayer("picasa");
        playerInstance.setup({
        id:'picasa',
        controls: true,
        displaytitle: true,

        flashplayer: "//ssl.p.jwpcdn.com/player/v/7.12.5/jwplayer.flash.swf",
        width: "100%",
        height: "100%",
        aspectratio: "16:9",
        fullscreen: "true",
        provider: 'http',
        autostart: false,
        image:'http://localhost/viral/viralvideo.jpg',
            sources: [{file:"http://localhost/srt/43534234/viral022018SD.MP4",label:"SD",type: "video/mp4"},{file:"http://localhost/srt/43534234/viral022018HD.MP4",label:"HD",type: "video/mp4",default: true}],
            sharing:{
                link: "",
                code: "",
                heading: "Share",
                sites: ["facebook","twitter","tumblr","googleplus","reddit","linkedin","interest","email"],
            },
sharing:{
                link: "",
                code: "",
                heading: "Share",
                sites: ["facebook","twitter","tumblr","googleplus","reddit","linkedin","interest","email"],
            },
tracks: [{
            file: 'http://localhost/srt/viralvideo022018.srt',
            label: 'English',
            kind: 'captions',
            "default":true
}],

     captions: {
        color: '#FFEB3B',
        fontSize: 14,
        fontFamily: 'Scada, Hanuman, sans-serif, Verdana, cursive',
        fontOpacity: 100,
        backgroundOpacity: 0,
backgroundColor: '#000000',
        edgeStyle: 'raised',
        windowColor: '#000000',
        windowOpacity: 0
    },
skin: {
        name: 'prime',
    },




          });

</script>
</body>
</html>

Answer 1

请试试这个正则表达式：

{\s*file\s*:\s*["']\s*(http[^"']+\.mp4)

在这里试试：https://regex101.com/r/rmgKId/2

匹配的 URL 在组 1 中。

（编辑：添加 \.mp4 使其特定于那些文件）

编辑：要在 PHP 中实施，通常您需要执行以下操作：

preg_match_all('/{\s*file\s*:\s*["\']\s*(http[^"\']+\.mp4)/i', $subject,
    $result, PREG_PATTERN_ORDER);
$result = $result[1];

$result 将是正则表达式中与编号组 1 匹配的所有文本的数组。但我把它留给你插入上面的代码（更改变量名称以匹配你想要的）。

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