Python argparse 默认值不起作用

Question

我正在试验 argparse，该程序可以运行，但默认值不起作用。这是我的代码：

'''This simple program helps you in understanding how to feed the user input from command line and to show help on passing invalid argument.'''

import argparse
import sys

def calc(args):
    #Enable variables within the function to take on values from 'args' object. 
    operation = args.operation
    x = args.x
    y = args.y

    if (operation == "add"):
        return x + y
    elif (operation == "sub"):
        return x - y

parser = argparse.ArgumentParser(description="This is a summing program")   #parser is an object of the class Argument Parser.
parser.add_argument("x", type=float, default=1.0, help="What is the first number?") #add_argument is a method of the class ArgumentParser.
parser.add_argument("y", type=float, default=1.0, help='What is the second number?')
parser.add_argument("operation", type=str, default="add", help='What operation? Can choose add, sub, mul, or div')
args = parser.parse_args()
print(str(calc(args)))

这个简单的程序可以工作，但是尝试在没有值的情况下调用它 returns 出现以下错误：

usage: cmdline.py [-h] x y operation
cmdline.py: error: the following arguments are required: x, y, operation

我哪里错了？

Answer 1

更改这些行以指示您需要命名的可选命令行参数（因此 "-x" 而不是 "x"）：

parser.add_argument("-x", type=float, default=1.0, help="What is the first number?") #add_argument is a method of the class ArgumentParser.
parser.add_argument("-y", type=float, default=1.0, help='What is the second number?')

Answer 2

你不见了nargs='?'。以下作品：

import argparse
import sys 

def calc(args):
    #Enable variables within the function to take on values from 'args' object. 
    operation = args.operation
    x = args.x
    y = args.y

    if (operation == "add"):
        return x + y 
    elif (operation == "sub"):
        return x - y 

parser = argparse.ArgumentParser(description="This is a summing program")   #parser is an object of the class Argument Parser.
parser.add_argument("x", nargs='?', type=float, default=1.0, help="What is the first number?") #add_argument is a method of the class ArgumentParser.
parser.add_argument("y", nargs='?', type=float, default=1.0, help='What is the second number?')
parser.add_argument("operation", nargs='?', type=str, default="add", help='What operation? Can choose add, sub, mul, or div')
args = parser.parse_args()
print(str(calc(args)))

Answer 3

@jbcoe - 我认为您的代码中有一些错别字，但谢谢，它有效！这是解决方案，已清理：

'''This simple program helps you in understanding how to feed the user input from command line and to show help on passing invalid argument. It uses the argparse module.'''

import argparse

def calc(args):
    #Enable variables within the function to take on values from 'args' object. 
    operation = args.operation
    x = args.x
    y = args.y

    if (operation == "add"):
        return x + y
    elif (operation == "sub"):
        return x - y

parser = argparse.ArgumentParser(description="This is a summing program")   #parser is an object of the class Argument Parser.
parser.add_argument("x", nargs='?', type=float, default=1.0, help="What is the first number?") #add_argument is a method of the class ArgumentParser.
parser.add_argument("y", nargs='?', type=float, default=2.0, help='What is the second number?')
parser.add_argument("operation", nargs='?', type=str, default="add", help='What operation? Can choose add, sub, mul, or div')
args = parser.parse_args()
print(str(calc(args)))

Python argparse 默认值不起作用

Python argparse default values not working

python

argparse