如何 select 每个级别都有不同的用户和用户进度
How to select every level with different user and user progress
我想制作一个学习应用程序,每个级别都有完成的问题进度跟踪。我有 2 个 table,其中包含所有级别及其问题计数,还有一个 table,用于保存每个级别的用户进度(已完成的问题)。这是记录,
等级table:
+----------+----------------------+-------------+--------+
| id_level | name | jumlah_soal | id_sub |
+----------+----------------------+-------------+--------+
| 1 | Basic Level 1 | 5 | 1 |
| 2 | Basic Level 2 | 6 | 1 |
| 3 | Basic Level 3 | 7 | 1 |
| 8 | Intermediate Level 1 | 5 | 2 |
| 9 | Intermediate Level 2 | 5 | 2 |
| 10 | Intermediate Level 3 | 5 | 2 |
..........................................................
进度Table:
+-----------------+---------+-------------+----------+
| id_progreslevel | id_user | completed | id_level |
+-----------------+---------+-------------+----------+
| 1 | 1 | 2 | 1 |
| 2 | 1 | 3 | 2 |
| 3 | 2 | 2 | 1 |
+-----------------+---------+-------------+----------+
当我使用以下查询加入 table 时
SELECT IFNULL(progreslevel.id_user, 1) as id_user,
-> level.*, IFNULL(progreslevel.completed, 0) as completedquestions
-> FROM level LEFT JOIN progreslevel
-> ON level.id_level = progreslevel.id_level
-> WHERE level.id_sub = 1
-> HAVING id_user = 1;
它查询我想要的:
+---------+----------+---------------+-------------+--------+--------------------+
| id_user | id_level | name | jumlah_soal | id_sub | completed questions |
+---------+----------+---------------+-------------+--------+--------------------+
| 1 | 1 | Basic Level 1 | 5 | 1 | 2 |
| 1 | 2 | Basic Level 2 | 6 | 1 | 3 |
| 1 | 3 | Basic Level 3 | 7 | 1 | 0 |
+---------+----------+---------------+-------------+--------+--------------------+
但是,当我尝试更改为查询用户 ID = 2 的进度时,它变成了这样:
+---------+----------+---------------+-------------+--------+--------------------+
| id_user | id_level | name | jumlah_soal | id_sub | completed questions |
+---------+----------+---------------+-------------+--------+--------------------+
| 2 | 1 | Basic Level 1 | 5 | 1 | 2 |
| 2 | 3 | Basic Level 3 | 7 | 1 | 0 |
+---------+----------+---------------+-------------+--------+--------------------+
是的,Basic Level 2 没有了,因为用户 2 还没有完成,但用户 1 完成了。
这就是我卡住的地方,我想无论我选择哪个用户,它总是查询所有级别,即使其他用户已经完成了。应该是这样的:
+---------+----------+---------------+-------------+--------+--------------------+
| id_user | id_level | name | jumlah_soal | id_sub | completed questions |
+---------+----------+---------------+-------------+--------+--------------------+
| 2 | 1 | Basic Level 1 | 5 | 1 | 2 |
| 2 | 2 | Basic Level 2 | 6 | 1 | 0 |
| 2 | 3 | Basic Level 3 | 7 | 1 | 0 |
+---------+----------+---------------+-------------+--------+--------------------+
我该如何实现?
提前致谢,抱歉,如果您对我的解释或数据库感到头晕,我会尽力翻译它,所以它是可以理解的
我不太确定我是否理解要求,但我认为您正在寻找这样的东西...
SELECT l.*
, 2 id_user
, COALESCE(MAX(p.completed),0) completed_questions
FROM level l
LEFT
JOIN progress p
ON p.id_level = l.id_level
AND p.id_user = 2
WHERE l.id_sub = 1
GROUP
BY l.id_level;
我想制作一个学习应用程序,每个级别都有完成的问题进度跟踪。我有 2 个 table,其中包含所有级别及其问题计数,还有一个 table,用于保存每个级别的用户进度(已完成的问题)。这是记录,
等级table:
+----------+----------------------+-------------+--------+
| id_level | name | jumlah_soal | id_sub |
+----------+----------------------+-------------+--------+
| 1 | Basic Level 1 | 5 | 1 |
| 2 | Basic Level 2 | 6 | 1 |
| 3 | Basic Level 3 | 7 | 1 |
| 8 | Intermediate Level 1 | 5 | 2 |
| 9 | Intermediate Level 2 | 5 | 2 |
| 10 | Intermediate Level 3 | 5 | 2 |
..........................................................
进度Table:
+-----------------+---------+-------------+----------+
| id_progreslevel | id_user | completed | id_level |
+-----------------+---------+-------------+----------+
| 1 | 1 | 2 | 1 |
| 2 | 1 | 3 | 2 |
| 3 | 2 | 2 | 1 |
+-----------------+---------+-------------+----------+
当我使用以下查询加入 table 时
SELECT IFNULL(progreslevel.id_user, 1) as id_user,
-> level.*, IFNULL(progreslevel.completed, 0) as completedquestions
-> FROM level LEFT JOIN progreslevel
-> ON level.id_level = progreslevel.id_level
-> WHERE level.id_sub = 1
-> HAVING id_user = 1;
它查询我想要的:
+---------+----------+---------------+-------------+--------+--------------------+
| id_user | id_level | name | jumlah_soal | id_sub | completed questions |
+---------+----------+---------------+-------------+--------+--------------------+
| 1 | 1 | Basic Level 1 | 5 | 1 | 2 |
| 1 | 2 | Basic Level 2 | 6 | 1 | 3 |
| 1 | 3 | Basic Level 3 | 7 | 1 | 0 |
+---------+----------+---------------+-------------+--------+--------------------+
但是,当我尝试更改为查询用户 ID = 2 的进度时,它变成了这样:
+---------+----------+---------------+-------------+--------+--------------------+
| id_user | id_level | name | jumlah_soal | id_sub | completed questions |
+---------+----------+---------------+-------------+--------+--------------------+
| 2 | 1 | Basic Level 1 | 5 | 1 | 2 |
| 2 | 3 | Basic Level 3 | 7 | 1 | 0 |
+---------+----------+---------------+-------------+--------+--------------------+
是的,Basic Level 2 没有了,因为用户 2 还没有完成,但用户 1 完成了。 这就是我卡住的地方,我想无论我选择哪个用户,它总是查询所有级别,即使其他用户已经完成了。应该是这样的:
+---------+----------+---------------+-------------+--------+--------------------+
| id_user | id_level | name | jumlah_soal | id_sub | completed questions |
+---------+----------+---------------+-------------+--------+--------------------+
| 2 | 1 | Basic Level 1 | 5 | 1 | 2 |
| 2 | 2 | Basic Level 2 | 6 | 1 | 0 |
| 2 | 3 | Basic Level 3 | 7 | 1 | 0 |
+---------+----------+---------------+-------------+--------+--------------------+
我该如何实现? 提前致谢,抱歉,如果您对我的解释或数据库感到头晕,我会尽力翻译它,所以它是可以理解的
我不太确定我是否理解要求,但我认为您正在寻找这样的东西...
SELECT l.*
, 2 id_user
, COALESCE(MAX(p.completed),0) completed_questions
FROM level l
LEFT
JOIN progress p
ON p.id_level = l.id_level
AND p.id_user = 2
WHERE l.id_sub = 1
GROUP
BY l.id_level;