从文件读取并写入另一个文件 python

Question

我有一个文件，内容如下，

to-56  Olive  850.00  10 10
to-78  Sauce  950.00  25 20
to-65  Green  100.00   6 10

如果第4列数据小于或等于第5列，数据应该写入第二个文件。
我尝试了下面的代码，但第二个文件中只保存了 'to-56 Olive' 。我不知道我在这里做错了什么。

file1=open("inventory.txt","r")
file2=open("purchasing.txt","w")
data=file1.readline()
for line in file1:

    items=data.strip()
    item=items.split()

    qty=int(item[3])
    reorder=int(item[4])

    if qty<=reorder:
        file2.write(item[0]+"\t"+item[1]+"\n")


file1.close()
file2.close()

Answer 1

我已经稍微更改了您的代码，您需要做的就是遍历文件中的行 - 如下所示：

file1=open("inventory.txt","r")
file2=open("purchasing.txt","w")

# Iterate over each line in the file
for line in file1.readlines():

    # Separate each item in the line
    items=line.split()

    # Retrieve important bits
    qty=int(items[3])
    reorder=int(items[4])

    # Write to the file if conditions are met
    if qty<=reorder:
        file2.write(items[0]+"\t"+items[1]+"\n")

# Release used resources
file1.close()
file2.close()

这是 purchasing.txt 中的输出：

to-56   Olive
to-65   Green

Answer 2

您只阅读了一行输入。所以，你最多只能有一行输出。

我看你的代码有点"old school"。这里有一个更 "modern" 和 Pythonic 的版本。

# Modern way to open files. The closing in handled cleanly
with open('inventory.txt', mode='r') as in_file, \
     open('purchasing.txt', mode='w') as out_file:

    # A file is iterable
    # We can read each line with a simple for loop
    for line in in_file:

        # Tuple unpacking is more Pythonic and readable
        # than using indices
        ref, name, price, quantity, reorder = line.split()

        # Turn strings into integers
        quantity, reorder = int(quantity), int(reorder)

        if quantity <= reorder:
            # Use f-strings (Python 3) instead of concatenation
            out_file.write(f'{ref}\t{name}\n')

从文件读取并写入另一个文件 python

Read from file and write to another python

python

file-handling