硬币被抛出，直到一侧连续跌落 3 次

Question

我是编程新手，在完成一项任务时遇到问题：

Coin is thrown until one side falls three times in a row

int throwing = 0;

int tail=0;
int head=0;
int counter= 0;
Random rnd = new Random();

do
{
    throwing = rnd.Next(1, 3);
    Console.WriteLine(bacanje);
    counter++;

    if (throwing == 1)
    {
        tail++;
    }
    else if (throwing == 2)
    {
        head++;
    }

} while (tail != 3 && head!= 3);

所以我的问题是它不想连续 3 次，当结果如下时程序退出：头、头、尾、头。它应该是：头，头，头。

不确定要更改什么代码，如果有人有什么建议，我将不胜感激。谢谢

Answer 1

如果投掷发生变化，您永远不会为另一个重置计数器，您只需将另一个重置为 0

if (throwing == 1)
{
    tail++;
    head = 0;
}
else if (throwing == 2)
{
    head++;
    tail = 0;
}

硬币被抛出，直到一侧连续跌落 3 次

Coin is thrown until one side falls three times in a row

c#

c#-2.0