Xml 中的断言
Assertion in Xml
我想在 xml 文件中找到一个特定的键,并想用该特定键的预期值断言实际值。
例如:这是一个 xml 文件,我想断言学生 ID 是否为 493,
这种情况下可以使用xmlUnit吗?或者在 java.
的帮助下以简单的方式提供其他方法
<?xml version = "1.0"?>
<class>
<student id="393">
<name>Rajiv</name>
<age>18</age>
</student>
<student id="493">
<name>Candie</name>
<age>19</age>
</student>
</class>
xmlunit 库适用于整个文件处理和匹配,但对于单个值 "native" XPath 更适合恕我直言。例如:
import org.w3c.dom.Document;
import javax.xml.xpath.XPath;
import javax.xml.xpath.XPathFactory;
Document xmlDocument = ...
XPath xPath = XPathFactory.newInstance().newXPath();
String expression = "/student[1]/@id";
String actualValue = xPath.evaluate(expressiong, xmlDocument);
assertEquals( "493", actualValue );
有关示例,请参阅 Intro to XPath with Java。
import javax.xml.parsers.DocumentBuilderFactory;
import javax.xml.parsers.DocumentBuilder;
import org.w3c.dom.Document;
import org.w3c.dom.NodeList;
import org.w3c.dom.Node;
import org.w3c.dom.Element;
import java.io.File;
File fXmlFile = new File("file.xml");
DocumentBuilderFactory dbFactory = DocumentBuilderFactory.newInstance();
DocumentBuilder dBuilder = dbFactory.newDocumentBuilder();
Document doc = dBuilder.parse(fXmlFile);
NodeList nList = doc.getElementsByTagName("student");
System.out.println("----------------------------");
List studentList = new ArrayList();
for (int temp = 0; temp < nList.getLength(); temp++) {
Node nNode = nList.item(temp);
if (nNode.getNodeType() == Node.ELEMENT_NODE) {
Element eElement = (Element) nNode;
studentId = eElement.getAttribute("id"));
//In above we will get studentID one by one . you can add into one list and finally check expected studentid is present or not.
studentList.add(studentId);
}
}
我们将获取 studentList 中的所有学生,然后检查特定学生是否存在。
我想在 xml 文件中找到一个特定的键,并想用该特定键的预期值断言实际值。
例如:这是一个 xml 文件,我想断言学生 ID 是否为 493, 这种情况下可以使用xmlUnit吗?或者在 java.
的帮助下以简单的方式提供其他方法<?xml version = "1.0"?>
<class>
<student id="393">
<name>Rajiv</name>
<age>18</age>
</student>
<student id="493">
<name>Candie</name>
<age>19</age>
</student>
</class>
xmlunit 库适用于整个文件处理和匹配,但对于单个值 "native" XPath 更适合恕我直言。例如:
import org.w3c.dom.Document;
import javax.xml.xpath.XPath;
import javax.xml.xpath.XPathFactory;
Document xmlDocument = ...
XPath xPath = XPathFactory.newInstance().newXPath();
String expression = "/student[1]/@id";
String actualValue = xPath.evaluate(expressiong, xmlDocument);
assertEquals( "493", actualValue );
有关示例,请参阅 Intro to XPath with Java。
import javax.xml.parsers.DocumentBuilderFactory;
import javax.xml.parsers.DocumentBuilder;
import org.w3c.dom.Document;
import org.w3c.dom.NodeList;
import org.w3c.dom.Node;
import org.w3c.dom.Element;
import java.io.File;
File fXmlFile = new File("file.xml");
DocumentBuilderFactory dbFactory = DocumentBuilderFactory.newInstance();
DocumentBuilder dBuilder = dbFactory.newDocumentBuilder();
Document doc = dBuilder.parse(fXmlFile);
NodeList nList = doc.getElementsByTagName("student");
System.out.println("----------------------------");
List studentList = new ArrayList();
for (int temp = 0; temp < nList.getLength(); temp++) {
Node nNode = nList.item(temp);
if (nNode.getNodeType() == Node.ELEMENT_NODE) {
Element eElement = (Element) nNode;
studentId = eElement.getAttribute("id"));
//In above we will get studentID one by one . you can add into one list and finally check expected studentid is present or not.
studentList.add(studentId);
}
}
我们将获取 studentList 中的所有学生,然后检查特定学生是否存在。