SeekBar.onProgressChanged() 的未知重复

Question

如果我通过 seek.setProgress(1) 设置 seekbarprogress 的最小值并通过if 语句请查看下面的代码并记录。

public class MainActivity extends AppCompatActivity {
SeekBar seek;
@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main);
    seek=(SeekBar) findViewById(R.id.myseek);
    seek.setMax(20);
    seek.setProgress(1);
    seek.setOnSeekBarChangeListener(new SeekBar.OnSeekBarChangeListener() {
        @Override
        public void onProgressChanged(SeekBar seekBar, int progress, boolean fromUser) {
            int min=1;
            if(progress<min){
                seek.setProgress(min);
            }
            Toast.makeText(getApplicationContext(), Integer.toString(progress), Toast.LENGTH_SHORT).show();
            Log.i("test",Integer.toString(progress));
        }
        @Override
        public void onStartTrackingTouch(SeekBar seekBar) {
        }
        @Override
        public void onStopTrackingTouch(SeekBar seekBar) {
        }
    });

}
}




   05-25 11:00:41.834 1520-1520/com.example.dyno.seekbartimer I/test: 0
   05-25 11:00:41.846 1520-1520/com.example.dyno.seekbartimer I/test: 1
   05-25 11:00:41.849 1520-1520/com.example.dyno.seekbartimer I/test: 0
   05-25 11:00:41.861 1520-1520/com.example.dyno.seekbartimer I/test: 1
   05-25 11:00:41.864 1520-1520/com.example.dyno.seekbartimer I/test: 0
   05-25 11:00:41.867 1520-1520/com.example.dyno.seekbartimer I/test: 1
   05-25 11:00:41.870 1520-1520/com.example.dyno.seekbartimer I/test: 0

正如你可能看到的，当我将指针拉到最小位置时，即 1 0,1 重复自己的次数。如果在那里放置一些方法并且它开始重复自己，那将是可怕的......谢谢

Answer 1

您可以在设置进度时禁用侦听器，并在设置后启用它。

@Override
    public void onProgressChanged(SeekBar seekBar, int progress, boolean fromUser) {
        seek.setOnSeekBarChangeListener(null);
        int min=1;
        if(progress<min){
            seek.setProgress(min);
        }
        seek.setOnSeekBarChangeListener(this);  
        Toast.makeText(getApplicationContext(), Integer.toString(progress), Toast.LENGTH_SHORT).show();
        Log.i("test",Integer.toString(progress));
    }

Answer 2

这是因为seek.setProgress(min);会触发OnSeekBarChangeListener.onProgressChanged

为防止这种情况发生，请避免在 progressChanged 中更改 seekBar 的进度。如果必须这样做，则使用以下方法：

seek.setOnSeekBarChangeListener(new SeekBar.OnSeekBarChangeListener() {
        @Override
        public void onProgressChanged(SeekBar seekBar, int progress, boolean fromUser) {
            int min=1;
            if(progress<min){
                seekBar.setOnSeekBarChangeListener(null);
                seek.setProgress(min);
                seekBar.setOnSeekBarChangeListener(this);
                return;

            }
            Toast.makeText(getApplicationContext(), Integer.toString(progress), Toast.LENGTH_SHORT).show();
            Log.i("test",Integer.toString(progress));
        }
        @Override
        public void onStartTrackingTouch(SeekBar seekBar) {
        }
        @Override
        public void onStopTrackingTouch(SeekBar seekBar) {
        }
    });

SeekBar.onProgressChanged() 的未知重复

Unknown repetition of SeekBar.onProgressChanged()

java

android

seekbar