Laravel

Question

我正在使用 Laravel 5.5，我想处理来自自定义处理程序的自定义异常，而不是来自 app\Exceptions\Handler.php。现在，如果用户提交的表单中的某些字段为空，我会捕获异常。它像这样完美地工作：

ProfileController.php:

public function update(Request $request, $id){
    $this->guzzleService->put(
        $request,
        ApiEndPoints::UPDATE_PROFILE . $id,
        true
    );

    return back()->with('SavedCorrectly', 'Changes saved correctly');
}

app\Exceptions\Handler.php

public function render($request, Exception $exception)
{
    if($exception instanceof ClientException && $exception->getCode() == 422)
        return back()->withErrors(
            json_decode((string) $exception->getResponse()->getBody(), TRUE)["errors"]
        );

    return parent::render($request, $exception);
}

问题是我想重构它，让它保持这样：

ProfileController.php

public function update(Request $request, $id){
    try {
        $this->guzzleService->put(
            $request,
            ApiEndPoints::UPDATE_PROFILE . $id,
            true
        );

        return back()->with('SavedCorrectly', 'Cambios guardados correctamente');
    } catch(ClientException $exception) {
        if ($exception->getCode() == 500) throw new InternalServerErrorException;
        if ($exception->getCode() == 422) throw new UnprocessableEntityException;
    }
}

app\Exceptions\HttpExceptions\UnprocessableEntityException.php

<?php

namespace App\Exceptions\HttpExceptions;

use GuzzleHttp\Exception\ClientException;

class UnprocessableEntityException extends \Exception
{
    public function render($request, ClientException $exception)
    {
        return back()->withErrors(
            json_decode((string) $exception->getResponse()->getBody(), TRUE)["errors"]
        );
    }
}

但是我收到这个错误：

Type error: Argument 2 passed to App\Exceptions\HttpExceptions\UnprocessableEntityException::render() must be an instance of GuzzleHttp\Exception\ClientException, none given, called in ... \vendor\laravel\framework\src\Illuminate\Foundation\Exceptions\Handler.php on line 169

Answer 1

这是因为您传递了一个新的异常

public function update(Request $request, $id){
    try {
        $this->guzzleService->put(
            $request,
            ApiEndPoints::UPDATE_PROFILE . $id,
            true
        );

        return back()->with('SavedCorrectly', 'Cambios guardados correctamente');
    } catch(ClientException $exception) {
        if ($exception->getCode() == 500) throw new InternalServerErrorException((string) $exception->getResponse()->getBody());
        if ($exception->getCode() == 422) throw new UnprocessableEntityException((string) $exception->getResponse()->getBody());
    }
}

和

<?php

namespace App\Exceptions\HttpExceptions;

use GuzzleHttp\Exception\ClientException;

class UnprocessableEntityException extends \Exception
{
    public function render($request)
    {
        return back()->withErrors(
            json_decode((string) $this->message, TRUE)["errors"]
        );
    }
}

Laravel - 在自定义处理程序中捕获异常

Laravel - Catch exception in custom handler

render

exception

handler

laravel-5.5