C 程序跳过 printf 和 scanf 语句

Question

我下面的程序在 C 中执行凯撒密码。出于某种原因，在用户输入消息后，printf(" \nEnter key:") 和 scanf("%d", &key) 语句得到 "jumped" 结束。我的想法与输入缓冲区有关，输入的字符和换行符导致跳转（因此 fflush 尝试）。我如何防止这种行为？

#include <stdio.h>
#include <stdlib.h>

int main() {
    char message[50], ms;
    int i, key, choice;

    printf("Enter 1. to Encrypt, or 2. to Decrypt: ");
    scanf(" %d", &choice);

    printf("Enter a message to process: ");
    scanf(" %c", message);
    printf(" \nEnter key:");
    fflush(stdin);
    scanf("%d", &key);

    for (i = 0; message[i] != '[=10=]'; ++i) {
        ms = message[i];
        if (ms >= 'a' && ms <= 'z' && choice == 1) {
            ms = ms + key;
            if (ms >= 'a' && ms <= 'z' && choice == 2) {
                ms = ms - key;
                if (ms > 'z') {
                    ms = ms - 'z' + 'a' - 1;
                }
            }
            message[i] = ms;
        } else
        if (ms >= 'A' && ms <= 'Z' && choice == 1) {
            ms = ms + key;
            if (ms >= 'A' && ms <= 'Z' && choice == 2) {
                ms = ms - key;
            }
            if (ms > 'Z') {
                ms = ms - 'Z' + 'A' - 1;
            }
            message[i] = ms;
        }
        if (choice == 1) {
            printf(" \nEncrypted message: %s", message);}
        else if (choice == 2) {
            printf(" \nDecrypted message: %s", message);}
    }
}

Answer 1

您的代码中存在多个问题：

您输入消息的方式不正确：scanf(" %c", message); 将单个字节读入 message 第一个元素，甚至没有使其成为 C 字符串。改用它来阅读带有嵌入空格的消息：
```
scanf("%49[^\n]", message);
```
其余代码中存在逻辑错误：例如，您在仅在 choice == 1...[= 时执行的块内测试 choice == 2 16=]

这是一个简化版本：

#include <stdio.h>

int main() {
    char message[50];
    int i, key, choice;

    printf("Enter 1. to Encrypt, or 2. to Decrypt: ");
    if (scanf("%d", &choice) != 1)
        return 1;

    printf("\nEnter a message to process: ");
    if (scanf("%49[^\n]", message) != 1)
        return 1;
    printf("\nEnter key:");
    if (scanf("%d", &key) != 1)
        return 1;

    for (i = 0; message[i] != '[=11=]'; ++i) {
        int ms = message[i];
        if (ms >= 'a' && ms <= 'z') {
            if (choice == 1)
                ms = 'a' + ((ms - 'a') + key) % 26;
            if (choice == 2)
                ms = 'a' + ((ms - 'a') + 26 - key) % 26;
            message[i] = ms;
        } else
        if (ms >= 'A' && ms <= 'Z') {
            if (choice == 1)
                ms = 'A' + ((ms - 'A') + key) % 26;
            if (choice == 2)
                ms = 'A' + ((ms - 'A') + 26 - key) % 26;
            message[i] = ms;
        }
    }
    if (choice == 1)
        printf("\nEncrypted message: %s\n", message);
    if (choice == 2)
        printf("\nDecrypted message: %s\n", message);
    }
    return 0;
}

Answer 2

@ddisec 我在你的代码中注意到 3 mistakes。

首先是你的 scanf(" %c", message); 。这里你必须使用 %s (String).

其次结果打印语句应该在for-loop.

之外

第三次将 if(ms >= 'a' && ms <= 'z'&& choice == 2) 放在 if (ms >= 'a' && ms <= 'z' && choice == 1) 中没有任何意义。

试试这个更正后的代码：-

#include <stdio.h>
#include <stdlib.h>

int main()
{
    char message[50], ms;
    int i, key, choice;

    printf("Enter 1. to Encrypt, or 2. to Decrypt: ");
    scanf("%d", &choice);
    getchar();                                              // to handle unwanted newline.
    printf("Enter a message to process: ");
    scanf("%49[^\n]", message);
    printf(" \nEnter key:");
    scanf("%d", &key);

    for (i = 0; message[i] != '[=10=]'; ++i)
    {
        ms = message[i];
        if (ms >= 'a' && ms <= 'z' && choice == 1)
        {
            ms = ms + key;
        }
        else if (ms >= 'a' && ms <= 'z' && choice == 2)
        {
            ms = ms - key;
        }
        else if (ms > 'z')
            {
                ms = ms - 'z' + 'a' - 1;
            }
        else if (ms >= 'A' && ms <= 'Z' && choice == 1)
        {
            ms = ms + key;
        }
        else if (ms >= 'A' && ms <= 'Z' && choice == 2)
        {
            ms = ms - key;
        }
        else if (ms > 'Z')
        {
            ms = ms - 'Z' + 'A' - 1;
        }

        message[i] = ms; // Only single modification code needed.
    }
    if (choice == 1)
    {
        printf(" \nEncrypted message: %s", message);
    }
    else if (choice == 2)
    {
        printf(" \nDecrypted message: %s", message);
    }
}

C 程序跳过 printf 和 scanf 语句

C program skipping printf and scanf statements

c

encryption

printf

scanf

fflush