在 file.gz 中导出关键字

Question

我有一个 xxx.gz 文件，它包含以下一些文本字符：

Array
(
[f_name] => YOKICHI
[l_name] => KOSHIZAWA
[name] => YOKICHI KOSHIZAWA
[street_address] => 7164 fake
[city] => CANTON
[state] => MI
[zip] => 48187
[country] => United States
[phone] => 734-354-6599
[email] => ykoshizawxxa@att.net
[discount_percent] => 0.00
[discount_amount] => 0
[discount_items] => 
[shipping_region] => USA
[shipping_type] => 
[shipping_priority] => 
[shipping_options] => 
[shipping_total] => 0
)

我需要 PHP 源代码到运行在本地主机上，可以过滤然后导出以下信息：

| f_name | l_name | street_address | city | state | zip | phone | country

例如：

| YOKICHI | KOSHIZAWA | 7164 fake | CANTON | MI | 48187 | 734-354-6567 | United States

Answer 1

我给你做了代码，不要只是复制这个，试着用它来学习:)

// $source = file_get_contents($file);
$source = 'Array
(
[f_name] => YOKICHI
[l_name] => KOSHIZAWA
[name] => YOKICHI KOSHIZAWA
[street_address] => 7164 fake
[city] => CANTON
[state] => MI
[zip] => 48187
[country] => United States
[phone] => 734-354-6599
[email] => ykoshizawxxa@att.net
[discount_percent] => 0.00
[discount_amount] => 0
[discount_items] => 
[shipping_region] => USA
[shipping_type] => 
[shipping_priority] => 
[shipping_options] => 
[shipping_total] => 0
)';

// convert input to array
$arr = explode(PHP_EOL, $source);

// clean top and bottom of the array
array_shift($arr);
array_shift($arr);
array_pop($arr);

// init final array
$final = array();

foreach($arr as $v)
{
    $o = array();
    $v = preg_match_all('#\[([a-zA-Z0-9 _.-]+)\] => (.*)#', $v, $o);

    $key = $o[1][0];
    $val = (isset($o[2][0])) ? $o[2][0] : ''; 

    // fill final
    $final[$key] = $val;
}

// init the filtered array
$sort = array();
// keys you want to have in
$keys = array('f_name','l_name','street_address','city','state','zip','phone','country');

foreach($final as $k => $v)
{
    if(in_array($k, $keys))
    {
        $sort[$k] = $v;
    }
}

var_dump($sort);

在 file.gz 中导出关键字

Export keywords in file.gz

php

export

keyword