将列名与非零值连接起来

Question

有一个 table 有 ID、事件、日期。

当前脚本按id、event_type和日期统计事件，转置然后按当天事件类型的组合标记每个ID。

担心的是，如果出现新的事件类型，这会中断。

我希望找到一种方法，将所有非零计数的列名连接起来。理想情况下，此方法不涉及对事件进行硬编码。

data test;
infile datalines delimiter=':' truncover;
informat id 10.  event_dt DDMMYY10. event_type . event .;
input id event_dt event_type event;
datalines;
1:01-03-2017:BB:b1
1:01-03-2017:AA:A2
1:02-03-2017:CC:C1
2:01-03-2017:CC:C2
3:03-03-2017:BB:b2
4:02-03-2017:AA:A1
;
run;


proc sql;
    create table test2 as
    select distinct ID, event_dt format worddate. as event_dt, event_type, count(distinct event) as event_count
    from test 
    group by ID, event_dt, event_type;
quit;

proc transpose data=test2 out=test3 (drop =  _name_);
by id event_dt;
id event_type;
run;

proc stdize data=test3  out=test3z reponly missing=0;
   run;


proc sql;
    create table test4 as
    select event_dt,
    case when AA = 0 and BB = 0 and CC = 0 then 'No Event'
         when AA = 0 and BB = 0 and CC > 0 then 'CC only'
         when AA = 0 and BB > 0 and CC = 0 then 'BB only'
         when AA = 0 and BB > 0 and CC > 0 then 'BB & CC'
         when AA > 0 and BB = 0 and CC = 0 then 'AA only'
         when AA > 0 and BB = 0 and CC > 0 then 'AA & CC'
         when AA > 0 and BB > 0 and CC = 0 then 'AA & BB'
         when AA > 0 and BB > 0 and CC > 0 then 'AA & BB & CC'
         else 'Other' end as tag, count(id) as ID_COUNT
    from test3z group by 
        event_dt,
    case when AA = 0 and BB = 0 and CC = 0 then 'No Event'
         when AA = 0 and BB = 0 and CC > 0 then 'CC only'
         when AA = 0 and BB > 0 and CC = 0 then 'BB only'
         when AA = 0 and BB > 0 and CC > 0 then 'BB & CC'
         when AA > 0 and BB = 0 and CC = 0 then 'AA only'
         when AA > 0 and BB = 0 and CC > 0 then 'AA & CC'
         when AA > 0 and BB > 0 and CC = 0 then 'AA & BB'
         when AA > 0 and BB > 0 and CC > 0 then 'AA & BB & CC'
         else 'Other' end;
quit;

谢谢本

Answer 1

有人可能会说，转置和使用数组。

考虑这个替代方案——而不是通过处理一行中的显式列来分配标签值。

在遍历 id/date 组时计算标签值，在遍历 date/tag 组时对 id 进行排序和计数。

* same as in question;
proc sql;
    create table test2 as
    select distinct ID, event_dt format worddate. as event_dt, event_type, count(distinct event) as event_count
    from test 
    group by ID, event_dt, event_type;
quit;

* compute tag value (I call it type_list);
data test2a;
  length type_list ;
  do _n_ = 1 by 1 until (last.event_dt);
    set test2;
    by ID event_dt;
    type_list = catx(',',type_list,event_type);
  end;
  keep id event_dt type_list;
run;

proc sort data=test2a;
  by event_dt type_list;
run;

* count number of ids with same type list on each event day;
data want;
  do id_count = 1 by 1 until (last.type_list);
    set test2a;
    by event_dt type_list;
  end;
run;

您可以添加额外的逻辑和 tranwrd 以将 type_list（csv 列表）更改为更详细的表示（包含单词 and or & or only)

将列名与非零值连接起来

Concatenate column names with non zero values

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