在 C 中初始化一个信号量

Question

我正在尝试创建一个通用函数以在 C 中创建信号量，但我不确定名为 mode_t mode 的第三个参数的值。我读到 read/write 是标准权限，我想接受它。我需要使用的价值是多少？

这是我的实现：

sem_t * semaphore_create(char * name, int value){

    sem_t *sem;


    sem = sem_open(name, O_CREAT , **what to put here ?** , value);

    if(sem == SEM_FAILED){
        perror("Error semaphore_create!");
        exit(-1);
    }

  return sem;

}

Answer 1

sem = sem_open(name, O_CREAT , S_IRUSR | S_IWUSR, value);

将授予读写权限。

您可以查看 open(2) 其他模式选项的手册：

  The following symbolic constants are provided for mode:

              S_IRWXU  00700 user (file owner) has read, write and execute
                       permission

              S_IRUSR  00400 user has read permission

              S_IWUSR  00200 user has write permission

              S_IXUSR  00100 user has execute permission

              S_IRWXG  00070 group has read, write and execute permission

              S_IRGRP  00040 group has read permission

              S_IWGRP  00020 group has write permission

              S_IXGRP  00010 group has execute permission

              S_IRWXO  00007 others have read, write and execute permission

              S_IROTH  00004 others have read permission

              S_IWOTH  00002 others have write permission

              S_IXOTH  00001 others have execute permission

在 C 中初始化一个信号量

Initialising a semaphore in C

c

posix