PHP 使用 foreach 遍历 JSON
PHP Traverse through JSON using foreach
我一直在按照本指南使用两个不同的 API 创建一个应用程序,但该指南是旧的,因此其中一个 API 无法像指南中那样工作。我正在尝试从 google 地理编码 API 获取坐标并将它们粘贴到 Places for Web 中。我是 PHP 的新手,所以我按照指南的示例来遍历 JSON 对象,但整晚都在努力让它工作。
这是来自地点搜索 API
的 JSON 对象
{
"html_attributions":[ ],
"results":[
{
"geometry":{ },
"icon":"https://maps.gstatic.com/mapfiles/place_api/icons/restaurant-71.png",
"id":"d4b0fb0f7bf5b2ea7df896a0c120a68efae039cf",
"name":"Guadalajara Mexican Grill & Cantina",
"opening_hours":{ },
"photos":[
{
"height":2952,
"html_attributions":[ ],
"photo_reference":"CmRaAAAAfO4JKUaO8vCFM2dcu5LMu4mA4_HXQGJ1FyAnyJUre_kD6VOWiQj7tBEECx4AAct5AORIKipSYWg-Zprjlf8o-SFd7mBRGMXMVMwodFZ5KMLwPYPUhBnTTehGPkb9275pEhCkAqMwfmK29vYenk1wdwFvGhSIHR8ch6FONc99tGn4rVnesbuteg",
"width":5248
}
],
"place_id":"ChIJ27es4SWa3IARcvjmt3xL2Aw",
"price_level":2,
"rating":4.4,
"reference":"CmRRAAAA7Rx-l7juDX-1or5dfpK6qFcZ0trZ9cUNEUtKP2ziqHb2MhOE6egs-msJ2OdFKEuHhuNe-3Yk6yxUYwxCBqhDT3ci8pYZI4xYhPGyyDgDenbEU_8k84JiEtCGvj4bdIR0EhDR2Pqte5_kDUcCC9PJFVknGhQomvD4d7NBIhCFxI4i2iEc0w9UiA",
"scope":"GOOGLE",
"types":[ ],
"vicinity":"105 North Main Street, Lake Elsinore"
},
{ },
{ },
{ },
{ },
{ },
{ },
{ },
{ },
{ },
{ },
{ },
{ },
{ }
],
"status":"OK"
}
我可能正在尝试将所有照片引用抓取到一个数组中?然后将它们插入 google 的 Place Photos API。这是我的尝试:
更新
<?php
if(!empty($_GET["location"])){
//$API_key = "";
$maps_url = 'https://' .
'maps.googleapis.com/' .
'maps/api/geocode/json' .
'?address=' . urlencode($_GET['location']) .
'&key=';
$maps_json = file_get_contents($maps_url);
$maps_array = json_decode($maps_json, true);
$lat = $maps_array['results'][0]['geometry']['location']['lat'];
$lng = $maps_array['results'][0]['geometry']['location']['lng'];
$places_url = 'https://maps.googleapis.com/maps/api/place/nearbysearch/json?' .
'location=$lat,$lng' .
'&radius=1500' .
'&rankby=distance' .
'&key=';
$places_json = file_get_contents($places_url);
$places_array = json_decode($places_json, true);
if (!empty($places_array)) {
foreach ($places_array as $item) {
var_dump($places_array );
}
}
}
?>
<!DOCTYPE html>
<html lang="en">
<head>
<title>What is Here?</title>
</head>
<body>
<h1>Type in a location</h1>
<p>This program will display pictures of places to go in that area</p>
<form action ="">
<input type ="text" name ="location"/>
<button type ="submit">Go!</button>
</form>
<br/>
<?php
echo "$lat $lng";
?>
似乎无法让 foreach 循环执行任何操作
$lat,$lng
变量或 API 调用是您的第一个问题,foreach 循环是第二个问题。
json_decode($someJSON, true);
从您的 json 创建一个关联数组,因此您不能使用 ->
箭头,它们是针对对象的。 More about this。
没有$item->photo_reference
,使用:
$results = $places_array["results"];
foreach ($results as $item) {
echo $item["photos"]["photo_reference"];
}
无效的请求意味着错误的url或错误的参数
如果 $lat 和 $lng 是变量,那么插值将无法使用单引号尝试使用这样的双引号
"location=$lat,$lng"
$places_url = 'https://maps.googleapis.com/maps/api/place/nearbysearch/json?' .
"location=$lat,$lng" .
'&rankby=distance' .
'&key=mykey';
你应该删除半径或距离你不能在文档中同时获得它们
https://developers.google.com/places/web-service/search?hl=en-419
这是我在本地主机上运行的修改代码,请注意 $contextOptions 你不应该将它复制到你的代码中这是使 file_get_contents 在我的机器上运行的解决方法
之后 foreach 应该很简单,因为只是一个数组看看代码
$thelocation = "1600+Amphitheatre+Parkway,+Mountain+View,+CA";
$thekey = "someapikey";
$maps_url = 'https://' .
'maps.googleapis.com/' .
'maps/api/geocode/json' .
'?address=' . urlencode($thelocation) .
'&key=' . $thekey;
$contextOptions = array(
"ssl" => array(
"verify_peer" => false,
"verify_peer_name" => false,
),
);
$maps_json = file_get_contents($maps_url, 0, stream_context_create($contextOptions));// file_get_contents($maps_url);
$maps_array = json_decode($maps_json, true);
$lat = $maps_array['results'][0]['geometry']['location']['lat'];
$lng = $maps_array['results'][0]['geometry']['location']['lng'];
$places_url = 'https://maps.googleapis.com/maps/api/place/nearbysearch/json?' .
"location=$lat,$lng" .
'&rankby=distance' .
'&key='.$thekey;
//https://maps.googleapis.com/maps/api/place/nearbysearch/json?location=-33.8670522,151.1957362&rankby=distance&key=
$places_json = file_get_contents($places_url,0, stream_context_create($contextOptions));
$places_array = json_decode($places_json, true);
if (!empty($places_array)) {
foreach ($places_array["results"] as $item) {
echo $item["name"]."<br>";
}
}
这打印....简单
AVEonline.co
KRAV MAGA GLOBAL WORLD MAP
Mark Carvalho
Amyan
Moving the Planet
Sosta in Camper
NosCode
GLOBAL BUZZ
OptiClean
JI-SU TELECOM
Reel Thrillz
Clío Reconstrucción Histórica
AprimTek
Hayjayshop
NHAV
gitanos.cat
Being Digitall
Directory+
AdExperts
Optical Spectroscopy and Nanomaterials Group
我一直在按照本指南使用两个不同的 API 创建一个应用程序,但该指南是旧的,因此其中一个 API 无法像指南中那样工作。我正在尝试从 google 地理编码 API 获取坐标并将它们粘贴到 Places for Web 中。我是 PHP 的新手,所以我按照指南的示例来遍历 JSON 对象,但整晚都在努力让它工作。 这是来自地点搜索 API
的 JSON 对象{
"html_attributions":[ ],
"results":[
{
"geometry":{ },
"icon":"https://maps.gstatic.com/mapfiles/place_api/icons/restaurant-71.png",
"id":"d4b0fb0f7bf5b2ea7df896a0c120a68efae039cf",
"name":"Guadalajara Mexican Grill & Cantina",
"opening_hours":{ },
"photos":[
{
"height":2952,
"html_attributions":[ ],
"photo_reference":"CmRaAAAAfO4JKUaO8vCFM2dcu5LMu4mA4_HXQGJ1FyAnyJUre_kD6VOWiQj7tBEECx4AAct5AORIKipSYWg-Zprjlf8o-SFd7mBRGMXMVMwodFZ5KMLwPYPUhBnTTehGPkb9275pEhCkAqMwfmK29vYenk1wdwFvGhSIHR8ch6FONc99tGn4rVnesbuteg",
"width":5248
}
],
"place_id":"ChIJ27es4SWa3IARcvjmt3xL2Aw",
"price_level":2,
"rating":4.4,
"reference":"CmRRAAAA7Rx-l7juDX-1or5dfpK6qFcZ0trZ9cUNEUtKP2ziqHb2MhOE6egs-msJ2OdFKEuHhuNe-3Yk6yxUYwxCBqhDT3ci8pYZI4xYhPGyyDgDenbEU_8k84JiEtCGvj4bdIR0EhDR2Pqte5_kDUcCC9PJFVknGhQomvD4d7NBIhCFxI4i2iEc0w9UiA",
"scope":"GOOGLE",
"types":[ ],
"vicinity":"105 North Main Street, Lake Elsinore"
},
{ },
{ },
{ },
{ },
{ },
{ },
{ },
{ },
{ },
{ },
{ },
{ },
{ }
],
"status":"OK"
}
我可能正在尝试将所有照片引用抓取到一个数组中?然后将它们插入 google 的 Place Photos API。这是我的尝试:
更新
<?php
if(!empty($_GET["location"])){
//$API_key = "";
$maps_url = 'https://' .
'maps.googleapis.com/' .
'maps/api/geocode/json' .
'?address=' . urlencode($_GET['location']) .
'&key=';
$maps_json = file_get_contents($maps_url);
$maps_array = json_decode($maps_json, true);
$lat = $maps_array['results'][0]['geometry']['location']['lat'];
$lng = $maps_array['results'][0]['geometry']['location']['lng'];
$places_url = 'https://maps.googleapis.com/maps/api/place/nearbysearch/json?' .
'location=$lat,$lng' .
'&radius=1500' .
'&rankby=distance' .
'&key=';
$places_json = file_get_contents($places_url);
$places_array = json_decode($places_json, true);
if (!empty($places_array)) {
foreach ($places_array as $item) {
var_dump($places_array );
}
}
}
?>
<!DOCTYPE html>
<html lang="en">
<head>
<title>What is Here?</title>
</head>
<body>
<h1>Type in a location</h1>
<p>This program will display pictures of places to go in that area</p>
<form action ="">
<input type ="text" name ="location"/>
<button type ="submit">Go!</button>
</form>
<br/>
<?php
echo "$lat $lng";
?>
似乎无法让 foreach 循环执行任何操作
$lat,$lng
变量或 API 调用是您的第一个问题,foreach 循环是第二个问题。
json_decode($someJSON, true);
从您的 json 创建一个关联数组,因此您不能使用 ->
箭头,它们是针对对象的。 More about this。
没有$item->photo_reference
,使用:
$results = $places_array["results"];
foreach ($results as $item) {
echo $item["photos"]["photo_reference"];
}
无效的请求意味着错误的url或错误的参数 如果 $lat 和 $lng 是变量,那么插值将无法使用单引号尝试使用这样的双引号 "location=$lat,$lng"
$places_url = 'https://maps.googleapis.com/maps/api/place/nearbysearch/json?' .
"location=$lat,$lng" .
'&rankby=distance' .
'&key=mykey';
你应该删除半径或距离你不能在文档中同时获得它们 https://developers.google.com/places/web-service/search?hl=en-419
这是我在本地主机上运行的修改代码,请注意 $contextOptions 你不应该将它复制到你的代码中这是使 file_get_contents 在我的机器上运行的解决方法
之后 foreach 应该很简单,因为只是一个数组看看代码
$thelocation = "1600+Amphitheatre+Parkway,+Mountain+View,+CA";
$thekey = "someapikey";
$maps_url = 'https://' .
'maps.googleapis.com/' .
'maps/api/geocode/json' .
'?address=' . urlencode($thelocation) .
'&key=' . $thekey;
$contextOptions = array(
"ssl" => array(
"verify_peer" => false,
"verify_peer_name" => false,
),
);
$maps_json = file_get_contents($maps_url, 0, stream_context_create($contextOptions));// file_get_contents($maps_url);
$maps_array = json_decode($maps_json, true);
$lat = $maps_array['results'][0]['geometry']['location']['lat'];
$lng = $maps_array['results'][0]['geometry']['location']['lng'];
$places_url = 'https://maps.googleapis.com/maps/api/place/nearbysearch/json?' .
"location=$lat,$lng" .
'&rankby=distance' .
'&key='.$thekey;
//https://maps.googleapis.com/maps/api/place/nearbysearch/json?location=-33.8670522,151.1957362&rankby=distance&key=
$places_json = file_get_contents($places_url,0, stream_context_create($contextOptions));
$places_array = json_decode($places_json, true);
if (!empty($places_array)) {
foreach ($places_array["results"] as $item) {
echo $item["name"]."<br>";
}
}
这打印....简单
AVEonline.co
KRAV MAGA GLOBAL WORLD MAP
Mark Carvalho
Amyan
Moving the Planet
Sosta in Camper
NosCode
GLOBAL BUZZ
OptiClean
JI-SU TELECOM
Reel Thrillz
Clío Reconstrucción Histórica
AprimTek
Hayjayshop
NHAV
gitanos.cat
Being Digitall
Directory+
AdExperts
Optical Spectroscopy and Nanomaterials Group