添加两个多项式并正确显示结果
Adding two polynomials and displaying the result properly
我的代码相当简单:
#include <cstdlib>
#include <iostream>
#include <string>
#include <vector>
#include <numeric>
#include <cmath>
using namespace std;
int main() {
int sizeOfPoly1;
cout<<"Size of first polynomial: ";
cin>>sizeOfPoly1;
vector<int> poly1(sizeOfPoly1);
cout<<"constant =";
cin>>poly1[0];
for (int i = 1; i <= (sizeOfPoly1-1); ++i)
{
cout<<"Insert x^"<<i<<": ";
cin>>poly1[i];
}
int sizeOfPoly2;
cout<<"Size of second polynomial: ";
cin>>sizeOfPoly2;
vector<int> poly2(sizeOfPoly2);
cout<<"constant =";
cin>>poly2[0];
for (int i = 1; i <= (sizeOfPoly2-1); ++i)
{
cout<<"Insert x^"<<i<<": ";
cin>>poly2[i];
}
int sizeOfResult;
//verifies which polynomial has more elements and makes the result the size of the biggest one
if (poly1.size() >= poly2.size()) sizeOfResult = poly1.size();
else sizeOfResult = poly2.size();
vector<int> result(sizeOfResult);
for(int i = 0; i<sizeOfResult; ++i) { result[i] = poly1[i] + poly2[i]; }
cout<<"Sum of the two polynomials: ";
for(int i = 0; i<sizeOfResult; ++i)
{
switch(i){
case 0: cout<<result[i]<<" "; break;
case 1: cout<<result[i]<<"x"<<" "; break;
default: cout<<result[i]<<"x^"<<i<<" "; break;
}
}
return 0;
}
我想要做的是让用户输入他们的多项式大小,然后输入常数,x^1,x^2 等等,然后 return 两者的总和多项式。此代码当前生成一些奇怪的东西,例如:
Sum of the two polynomials: 2 4x 6x^2 8x^3 1772060652x^4
当一个多项式向量的元素多于另一个时,如何防止发生此输出错误?
只需将它们设为相同大小并使用 std::transform
:
const auto sizeOfResult = std::max( poly1.size(), poly2.size() );
poly1.resize( sizeOfResult );
poly2.resize( sizeOfResult );
vector<int> result(sizeOfResult);
std::transform( poly1.begin(), poly1.end(), poly2.begin(), result.begin(),
[]( int a, int b ) { return a+b; } );
这是一个简单的解决方案,但开销很小。更有效的解决方案:
auto p = poly1.size() < poly2.size() ? std::tie( poly1, poly2 ) : std::tie( poly2, poly1 );
std::vector<int> result( std::get<1>( p ) );
for( size_t i = 0; i != std::get<0>( p ).size(); ++i )
result[i] += std::get<0>( p )[i];
我的代码相当简单:
#include <cstdlib>
#include <iostream>
#include <string>
#include <vector>
#include <numeric>
#include <cmath>
using namespace std;
int main() {
int sizeOfPoly1;
cout<<"Size of first polynomial: ";
cin>>sizeOfPoly1;
vector<int> poly1(sizeOfPoly1);
cout<<"constant =";
cin>>poly1[0];
for (int i = 1; i <= (sizeOfPoly1-1); ++i)
{
cout<<"Insert x^"<<i<<": ";
cin>>poly1[i];
}
int sizeOfPoly2;
cout<<"Size of second polynomial: ";
cin>>sizeOfPoly2;
vector<int> poly2(sizeOfPoly2);
cout<<"constant =";
cin>>poly2[0];
for (int i = 1; i <= (sizeOfPoly2-1); ++i)
{
cout<<"Insert x^"<<i<<": ";
cin>>poly2[i];
}
int sizeOfResult;
//verifies which polynomial has more elements and makes the result the size of the biggest one
if (poly1.size() >= poly2.size()) sizeOfResult = poly1.size();
else sizeOfResult = poly2.size();
vector<int> result(sizeOfResult);
for(int i = 0; i<sizeOfResult; ++i) { result[i] = poly1[i] + poly2[i]; }
cout<<"Sum of the two polynomials: ";
for(int i = 0; i<sizeOfResult; ++i)
{
switch(i){
case 0: cout<<result[i]<<" "; break;
case 1: cout<<result[i]<<"x"<<" "; break;
default: cout<<result[i]<<"x^"<<i<<" "; break;
}
}
return 0;
}
我想要做的是让用户输入他们的多项式大小,然后输入常数,x^1,x^2 等等,然后 return 两者的总和多项式。此代码当前生成一些奇怪的东西,例如:
Sum of the two polynomials: 2 4x 6x^2 8x^3 1772060652x^4
当一个多项式向量的元素多于另一个时,如何防止发生此输出错误?
只需将它们设为相同大小并使用 std::transform
:
const auto sizeOfResult = std::max( poly1.size(), poly2.size() );
poly1.resize( sizeOfResult );
poly2.resize( sizeOfResult );
vector<int> result(sizeOfResult);
std::transform( poly1.begin(), poly1.end(), poly2.begin(), result.begin(),
[]( int a, int b ) { return a+b; } );
这是一个简单的解决方案,但开销很小。更有效的解决方案:
auto p = poly1.size() < poly2.size() ? std::tie( poly1, poly2 ) : std::tie( poly2, poly1 );
std::vector<int> result( std::get<1>( p ) );
for( size_t i = 0; i != std::get<0>( p ).size(); ++i )
result[i] += std::get<0>( p )[i];