使用运行时调用的抽象方法的值

Question

我正在尝试使用 here 中的 MyLocation class。在下面的代码中，我需要在实例化 MyLocation 的 class 中的任何位置访问变量 currentLat 和 currentLon。我不知道如何访问 currentLat 和 currentLon

的值

LocationResult locationResult = new LocationResult(){ @Override public void gotLocation(Location location){ currentLat = location.getLatitude(); currentLon = location.getLongitude(); }; } MyLocation myLocation = new MyLocation(); myLocation.getLocation(this, locationResult);

假设我想在这里

Double x =currentLoc;

如何获取？任何帮助将不胜感激

Answer 1

而不是匿名 class 使用你自己的 extends/implments LocationResult class/interface 并像这样添加 getter

    class MyLocationResult extends/implments LocationResult{
    double currentLat;
    double currentLon;

    @Override 
    public void gotLocation(Location location){ 
        currentLat = location.getLatitude(); 
        currentLon = location.getLongitude(); 
    };
    public double getCurrentLat(){
       return currentLat;
    }
    public double getCurrentLon (){
       return currentLon ;
    }
}

那你可以写

MyLocationResult locationResult = new MyLocationResult();
MyLocation myLocation = new MyLocation(); 
myLocation.getLocation(this, locationResult);

只要你需要 currentLat 或 currentLon，你就可以写

locationResult.getCurrentLat();

Answer 2

您可以为您的变量使用 static 修饰符并全局定义它们..

public static double currentLat; // defined globally...
public static double currentLon;

LocationResult locationResult = new LocationResult(){
   @Override
      public void  gotLocation(Location location){
      currentLat =location.getLatitude(); // assuming getLatitude() returns double or int
      currentLon = location.getLongitude();
    };
}
MyLocation myLocation = new MyLocation();
myLocation.getLocation(this, locationResult);

现在您可以在任何地方访问它们

double x =currentLon;
double y =currentLat;

使用运行时调用的抽象方法的值

Using value of abstract method called at runtime

java

android

abstract-class

android-location

abstract-methods