onSuccess 方法未在 android 中调用 firebase

Question

我正在尝试创建一个动态 link，当我尝试调试代码时，它正在调用回调方法 addOnSuccessListener 但之后它没有调用，或者我们说它正在跳过 onSuccess() 方法，我我不知道为什么会这样。

private void firebaseInvite() {
        FirebaseUser user = FirebaseAuth.getInstance().getCurrentUser();
        String uid = user.getUid();
        String url = "https://larky.funswitch.io/?invitedby=" + uid;
        FirebaseDynamicLinks.getInstance().createDynamicLink()
                .setLink(Uri.parse(url))
                .setDynamicLinkDomain("https://fmu3k.app.goo.gl")
                .setAndroidParameters(
                        new DynamicLink.AndroidParameters.Builder("io.funswitch.funrooster")
                                .setMinimumVersion(5)
                                .build())
                .buildShortDynamicLink()
                .addOnSuccessListener(shortDynamicLink -> {

在此之后我的调试器跳过这段代码并且它没有调用

 mInvitationUrl = shortDynamicLink.getShortLink();
                    mDatabase.child("Name").addListenerForSingleValueEvent(new ValueEventListener() {
                        @Override
                        public void onDataChange(@NonNull DataSnapshot dataSnapshot) {
                            String referrerName = dataSnapshot.getValue(String.class);
                            String subject = String.format("%s wants you to play MyExampleGame!", referrerName);
                            String invitationLink = mInvitationUrl.toString();
                            String msg = "Let's play MyExampleGame together! Use my referrer link: "
                                    + invitationLink;
                            String msgHtml = String.format("<p>Let's play MyExampleGame together! Use my "
                                    + "<a href=\"%s\">referrer link</a>!</p>", invitationLink);

                            Intent intent = new Intent(Intent.ACTION_SENDTO);
                            intent.setData(Uri.parse("mailto:")); // only email apps should handle this
                            intent.putExtra(Intent.EXTRA_SUBJECT, subject);
                            intent.putExtra(Intent.EXTRA_TEXT, msg);
                            intent.putExtra(Intent.EXTRA_HTML_TEXT, msgHtml);
                            if (intent.resolveActivity(getActivity().getPackageManager()) != null) {
                                startActivity(intent);
                            }
                        }

                        @Override
                        public void onCancelled(@NonNull DatabaseError databaseError) {

                        }
                    });

                });
    }

请帮帮我..

Answer 1

我解决了这是一个非常基本的愚蠢错误，我实际上正在做 link 没有在上面的代码中解析，因为我在动态 link 和动态 [=13] 中提到了两次 https =] 域从动态 link 域中删除 https 后我得到它的工作。

private void firebaseInvite() {
        FirebaseUser user = FirebaseAuth.getInstance().getCurrentUser();
        String uid = user.getUid();
        String url = "https://larky.funswitch.io/?invitedby=" + uid;
        FirebaseDynamicLinks.getInstance().createDynamicLink()
                .setLink(Uri.parse(url))
                .setDynamicLinkDomain("fmu3k.app.goo.gl")
                .setAndroidParameters(
                        new DynamicLink.AndroidParameters.Builder("io.funswitch.funrooster")
                                .setMinimumVersion(5)
                                .build())
                .buildShortDynamicLink()
                .addOnSuccessListener(shortDynamicLink -> {

 mInvitationUrl = shortDynamicLink.getShortLink();
                    mDatabase.child("Name").addListenerForSingleValueEvent(new ValueEventListener() {
                        @Override
                        public void onDataChange(@NonNull DataSnapshot dataSnapshot) {
                            String referrerName = dataSnapshot.getValue(String.class);
                            String subject = String.format("%s wants you to play MyExampleGame!", referrerName);
                            String invitationLink = mInvitationUrl.toString();
                            String msg = "Let's play MyExampleGame together! Use my referrer link: "
                                    + invitationLink;
                            String msgHtml = String.format("<p>Let's play MyExampleGame together! Use my "
                                    + "<a href=\"%s\">referrer link</a>!</p>", invitationLink);

                            Intent intent = new Intent(Intent.ACTION_SENDTO);
                            intent.setData(Uri.parse("mailto:")); // only email apps should handle this
                            intent.putExtra(Intent.EXTRA_SUBJECT, subject);
                            intent.putExtra(Intent.EXTRA_TEXT, msg);
                            intent.putExtra(Intent.EXTRA_HTML_TEXT, msgHtml);
                            if (intent.resolveActivity(getActivity().getPackageManager()) != null) {
                                startActivity(intent);
                            }
                        }

                        @Override
                        public void onCancelled(@NonNull DatabaseError databaseError) {

                        }
                    });

                });
    }

onSuccess 方法未在 android 中调用 firebase

onSuccess method not calling in firebase in android

android

firebase-invites

firebase-dynamic-links