连接字符串:两个字符串列表的 "Multiplication"
Concatenating Strings: "Multiplication" of two list of strings
对于字符串列表,
在此处将乘法运算定义为连接:
l1 = ['aa', 'bb', 'cc']
l2 = ['11', '22']
l3 = l1 op l2
预期输出:
l3 = ['aa11', 'aa22', 'bb11', 'bb22', 'cc11', 'cc22']
我们可以简单地使用
for l in l1:
for ll in l2:
l3.append(l+ll)
但如果听到 pythonic 解决方案,我将不胜感激。
from itertools import product
l1 = ['aa', 'bb', 'cc']
l2 = ['11', '22']
l3 = [x+y for (x,y) in product(l1,l2)]
print(l3)
但这实际上与您正在做的事情是一样的(前提是您更正了拼写错误 :P)
l3 = [a+b for a in l1 for b in l2]
对于字符串列表, 在此处将乘法运算定义为连接:
l1 = ['aa', 'bb', 'cc']
l2 = ['11', '22']
l3 = l1 op l2
预期输出:
l3 = ['aa11', 'aa22', 'bb11', 'bb22', 'cc11', 'cc22']
我们可以简单地使用
for l in l1:
for ll in l2:
l3.append(l+ll)
但如果听到 pythonic 解决方案,我将不胜感激。
from itertools import product
l1 = ['aa', 'bb', 'cc']
l2 = ['11', '22']
l3 = [x+y for (x,y) in product(l1,l2)]
print(l3)
但这实际上与您正在做的事情是一样的(前提是您更正了拼写错误 :P)
l3 = [a+b for a in l1 for b in l2]