json-ld 别名未解析

Question

我正在尝试学习 json-ld，但我在使用别名时遇到了一些问题。

当我使用具有以下上下文和文档的 JSON-ld 游乐场时：

{
  "@context": {
    "url": "@id",
    "a": "@type",
    "name": "http://schema.org/name",
    "schema": "http://schema.org/"
  },
  "url": "http://example.com/about#gregg",
  "a": "schema:Person",
  "name": "Gregg Kellogg"
}

这会正确压缩为：

{
  "@context": "http://schema.org/",
  "id": "http://example.com/about#gregg",
  "type": "Person",
  "name": "Gregg Kellogg"
}

在这里可以看到：https://json-ld.org/playground/#startTab=tab-compacted&json-ld=%7B%22%40context%22%3A%7B%22url%22%3A%22%40id%22%2C%22a%22%3A%22%40type%22%2C%22name%22%3A%22http%3A%2F%2Fschema.org%2Fname%22%2C%22schema%22%3A%22http%3A%2F%2Fschema.org%2F%22%7D%2C%22url%22%3A%22http%3A%2F%2Fexample.com%2Fabout%23gregg%22%2C%22a%22%3A%22schema%3APerson%22%2C%22name%22%3A%22Gregg%20Kellogg%22%7D&context=%7B%22%40context%22%3A%22http%3A%2F%2Fschema.org%2F%22%7D

然而，当我使用带有以下代码的 Python pyld 库时：

from pyld import jsonld
import json

doc = {
    "url": "http://example.com/about#gregg",
    "a": "schema:Person",
    "name": "Gregg Kellogg"
}

context = {
    "url": "@id",
    "a": "@type",
    "name": "http://schema.org/name",
    "schema" : "http://schema.org/"
  }

compacted = jsonld.compact(doc, context)

print(json.dumps(compacted, indent=2))

只打印上下文，不打印文档：

{
  "@context": {
    "url": "@id",
    "a": "@type",
    "name": "http://schema.org/name",
    "schema": "http://schema.org/"
  }
}

谁能解释一下为什么在我使用 pyld 库时没有应用别名以及我做错了什么？

非常感谢

Answer 1

两个例子不一样。 Python 示例的问题在于输入文档没有上下文。处理器首先扩展数据并将导致丢弃未知项。打印出展开后的数据就可以看出问题：

expanded = jsonld.expand(doc)
print(json.dumps(expanded, indent=2))

[]

如果在上下文中添加，然后展开，您将看到正确的数据：

from pyld import jsonld
import json

context = {
    "url": "@id",
    "a": "@type",
    "name": "http://schema.org/name",
    "schema" : "http://schema.org/"
}

doc = {
    "@context": context,
    "url": "http://example.com/about#gregg",
    "a": "schema:Person",
    "name": "Gregg Kellogg"
}

expanded = jsonld.expand(doc)
print(json.dumps(expanded, indent=2))

[
  {
    "@type": [
      "http://schema.org/Person"
    ],
    "http://schema.org/name": [
      {
        "@value": "Gregg Kellogg"
      }
    ],
    "@id": "http://example.com/about#gregg"
  }
]

为了匹配您的压缩游乐场示例，您需要添加上述上下文并使用 schema.org 上下文进行压缩：

...
compacted = jsonld.compact(doc, {"@context": "http://schema.org/"})
# or use the shortcut:
# compacted = jsonld.compact(doc, "http://schema.org/")
print(json.dumps(compacted, indent=2))

{
  "@context": "http://schema.org/",
  "id": "http://example.com/about#gregg",
  "type": "Person",
  "name": "Gregg Kellogg"
}

json-ld 别名未解析

json-ld alias not parsing

python

json

schema.org

json-ld