MongoDB 聚合:创建子文档
MongoDB Aggregation: creating subdocuments
我有一个 MongoDB 集合,其中包含如下文档:
{
"_id": ObjectId("..."),
"code": 22726,
"parent_code": 35481,
"parent_description": "posterdati",
},
{
"_id": ObjectId("..."),
"code": 22726,
"parent_code": 35484,
"parent_description": "vicesindaco",
},
{
"_id": ObjectId("..."),
"code": 22727,
"parent_code": 35487,
"parent_description": "prefettura",
}
我想使用 "code" 字段作为 _id 对它们进行 $group,创建一个包含 parent_code 和 parent_description:
的子文档数组
{
"code": 22726,
parents: [
{
"parent_code": 35481,
"parent_description": "posterdati"
},
{
"parent_code": 35484,
"parent_description": "vicesindaco"
}
]
},
{
"code": 22727,
parents: [
{
"parent_code": 35487,
"parent_description": "prefettura"
}
]
}
是否可以仅使用聚合框架?我在聚合框架文档中没有看到对子文档的引用,所以我认为不是...
谢谢大家。
您可以使用以下聚合管道来获得所需的结果:
db.collection.aggregate([
{
"$group": {
"_id": "$code",
"parents": {
"$addToSet": {
"parent_code": "$parent_code",
"parent_description": "$parent_description"
}
}
}
},
{
"$project": {
"_id": 0,
"code": "$_id",
"parents": 1
}
}
]);
输出:
/* 0 */
{
"result" : [
{
"parents" : [
{
"parent_code" : 35487,
"parent_description" : "prefettura"
}
],
"code" : 22727
},
{
"parents" : [
{
"parent_code" : 35484,
"parent_description" : "vicesindaco"
},
{
"parent_code" : 35481,
"parent_description" : "posterdati"
}
],
"code" : 22726
}
],
"ok" : 1
}
我有一个 MongoDB 集合,其中包含如下文档:
{
"_id": ObjectId("..."),
"code": 22726,
"parent_code": 35481,
"parent_description": "posterdati",
},
{
"_id": ObjectId("..."),
"code": 22726,
"parent_code": 35484,
"parent_description": "vicesindaco",
},
{
"_id": ObjectId("..."),
"code": 22727,
"parent_code": 35487,
"parent_description": "prefettura",
}
我想使用 "code" 字段作为 _id 对它们进行 $group,创建一个包含 parent_code 和 parent_description:
的子文档数组{
"code": 22726,
parents: [
{
"parent_code": 35481,
"parent_description": "posterdati"
},
{
"parent_code": 35484,
"parent_description": "vicesindaco"
}
]
},
{
"code": 22727,
parents: [
{
"parent_code": 35487,
"parent_description": "prefettura"
}
]
}
是否可以仅使用聚合框架?我在聚合框架文档中没有看到对子文档的引用,所以我认为不是...
谢谢大家。
您可以使用以下聚合管道来获得所需的结果:
db.collection.aggregate([
{
"$group": {
"_id": "$code",
"parents": {
"$addToSet": {
"parent_code": "$parent_code",
"parent_description": "$parent_description"
}
}
}
},
{
"$project": {
"_id": 0,
"code": "$_id",
"parents": 1
}
}
]);
输出:
/* 0 */
{
"result" : [
{
"parents" : [
{
"parent_code" : 35487,
"parent_description" : "prefettura"
}
],
"code" : 22727
},
{
"parents" : [
{
"parent_code" : 35484,
"parent_description" : "vicesindaco"
},
{
"parent_code" : 35481,
"parent_description" : "posterdati"
}
],
"code" : 22726
}
],
"ok" : 1
}