如何覆盖用户定义的 I/O 程序?

How to override user-defined I/O procedures?

我有一个抽象 class 和我的 read/write 方法用于未格式化的二进制流。我还有一些 classes 从抽象的继承而来,其中一些有我也想序列化的附加组件。

所以,我希望第一组方法充当 "default" 行为,并且在继承的 classes 中覆盖它的方法仅供那些特定的 class 使用es.

我试过这样实现它:

module m
    implicit none

    type, abstract :: a
        integer, public :: num
    contains
        procedure :: write_a
        procedure :: read_a

        generic            :: write(unformatted) => write_a
        generic            :: read(unformatted)  => read_a
    end type a

    type, extends(a) :: b
        integer, public :: num2
    contains
        procedure :: write_b
        procedure :: read_b

        generic :: write(unformatted) => write_b
        generic :: read(unformatted) => read_b
   end type b

    type, extends(a) :: c
    end type c

contains

    subroutine write_a(this, unit, iostat, iomsg)
        class(a), intent(in)    :: this
        integer, intent(in)         :: unit
        integer, intent(out)        :: iostat
        character(*), intent(inout) :: iomsg

        write(unit, iostat=iostat, iomsg=iomsg) this%num
    end subroutine write_a

    subroutine read_a(this, unit, iostat, iomsg)
        class(a), intent(inout) :: this
        integer, intent(in)         :: unit
        integer, intent(out)        :: iostat
        character(*), intent(inout) :: iomsg

        read(unit, iostat=iostat, iomsg=iomsg) this%num
    end subroutine read_a

    subroutine write_b(this, unit, iostat, iomsg)
        class(b), intent(in)    :: this
        integer, intent(in)         :: unit
        integer, intent(out)        :: iostat
        character(*), intent(inout) :: iomsg

        write(unit, iostat=iostat, iomsg=iomsg) this%num, this%num2
    end subroutine write_b

    subroutine read_b(this, unit, iostat, iomsg)
        class(b), intent(inout) :: this
        integer, intent(in)         :: unit
        integer, intent(out)        :: iostat
        character(*), intent(inout) :: iomsg

        read(unit, iostat=iostat, iomsg=iomsg) this%num, this%num2
    end subroutine read_b
end module m

program mwe
    use m

    implicit none

    class(a), allocatable :: o1, o2, o3

    o1 = b(1,2)
    o2 = c(3)

    open(123, file='test5.dat', form='unformatted')
        write(123) o1
    close(123)

    allocate(b :: o3)

    open(123, file='test5.dat', form='unformatted')
        read(123) o3
    close(123)

    write(*,*) o3%num, o3%num2
end program mwe

但我收到以下错误:

test5.f90(29): error #8638: The type/rank signature for arguments of this specific subroutine is identical to another specific subroutine that shares the same defined I/O.   [WRITE_A]
    subroutine write_a(this, unit, iostat, iomsg)
---------------^
test5.f90(86): error #6460: This is not a field name that is defined in the encompassing structure.   [NUM2]
    write(*,*) o3%num, o3%num2
--------------------------^

在我看来,class a 中的 write 方法无法被覆盖。我怎样才能正确实施它?

这不是完全与定义的 input/output 过程有关的问题,而是更广泛的通用绑定和类型绑定过程。

您的类型 b 具有类型绑定过程,就好像(通过扩展)它被定义为

type b
  integer, public :: num, num2
 contains
    procedure :: write_a, write_b
    procedure :: read_a, read_b
    generic   :: write(unformatted) => write_a, write_b
    generic   :: read(unformatted)  => read_a, read_n
end type

绑定 write_awrite_b 确实不明确(read_aread_b 也是如此)。 [有关其他地方的更多详细信息。]

您并不真正需要那些 write_aread_a 绑定,因此应该覆盖它们:

type, abstract :: a
    integer, public :: num
 contains
    procedure :: write => write_a
    procedure :: read => read_a

    generic   :: write(unformatted) => write
    generic   :: read(unformatted)  => read
end type a

type, extends(a) :: b
    integer, public :: num2
 contains
    procedure :: write => write_b
    procedure :: read => read_b
end type b

此处 b 类型的 writeread 绑定覆盖 a 类型的绑定。 write(unformatted)read(unformatted) 的通用绑定保留到 b.

中(现在已覆盖)绑定的映射