在使用 CASE 输出值的 T-SQL 语句中计算 SUM

Calculate SUM in T-SQL statement which uses CASE to output values

我有一个 table 包含在电子商务网站上购买的订单,第二个 table 详细说明每个订单的产品(基本上是订单项)。我的职责是计算每个订购产品的总成本和总重量,按产品分组。店主希望能够按重量或价值确定销量最高的产品。

两个table的结构是这样的:

订单

id
orderDate

订单行

id
orderId
productNodeId
productName
quantity
duration
frequency
subscription
unitPrice
unitWeight

虽然有些订单行是简单的一次性产品(因此计算总数很简单,即总重量为 quantity * unitWeight,总成本为 quantity * unitCost),但其他订单行是订阅,其中总重量将按 (duration/frequency) * unitWeight 计算,总成本将是 (duration/frequency) * unitCost.

我有以下 T-SQL 语句,它使用 CASE 来 return 总值 (运行 in SQL Server 2008R2 Express) :

SELECT 
  productNodeId AS id, 
  productName AS name, 
  quantity, 
  duration, 
  frequency, 
  subscription, 
  unitPrice,
  CASE   
    WHEN subscription = 1 THEN unitWeight*(duration/frequency)
  ELSE
    unitWeight*quantity
  END AS weight,
  CASE   
    WHEN subscription = 1 THEN unitPrice*(duration/frequency)
  ELSE
    unitPrice*quantity
  END AS total

FROM Order INNER JOIN OrderLine ON Order.id = OrderLine.orderId WHERE orderStatusId = 3

--GROUP BY productNodeId
ORDER BY total DESC

这在一定程度上有效。它输出以下值:

id   |  name     | quantity | duration | frequency  | subscription | unitPrice | weight | total
1105    Option C   1          24          1            1              2.50        18000    60.00
1105    Option C   1          24          2            1              2.50        9000     30.00
1104    Option B   1          24          2            1              2.50        9000     30.00
1105    Option C   1          24          2            1              2.50        10800    30.00
1105    Option C   1          4          1             1              2.50        2000     10.00
1107    Option A   1          0          0             0              2.80        600      2.80
1107    Option A   1          0          0             0              2.80        600      2.80
1121    Option D   1          0          0             0              2.80        400      2.80

不过,最后一部分是对总数求和。但是,我不能只执行上面代码中注释掉的 GROUP BY productNodeId 语句,因为它需要聚合 subscription 字段,这否定了条件 weighttotal逻辑。

我想知道是否有人可以建议如何让它工作,以便我可以 return 更正重量和价格的总和?

非常感谢。

我无法对此进行测试,但您应该能够对原始查询进行子查询,并按逻辑将您的分组应用于总字段,从而保持您的条件不变。

select id,name,quantity,duration,frequency,subscription,unitprice,weight,sum(total) as sumedtotal

 from (
SELECT 
  productNodeId AS id, 
  productName AS name, 
  quantity, 
  duration, 
  frequency, 
  subscription, 
  unitPrice,
  CASE   
    WHEN subscription = 1 THEN unitWeight*(duration/frequency)
  ELSE
    unitWeight*quantity
  END AS weight,
  CASE   
    WHEN subscription = 1 THEN unitPrice*(duration/frequency)
  ELSE
    unitPrice*quantity
  END AS total

FROM Order INNER JOIN OrderLine ON Order.id = OrderLine.orderId WHERE orderStatusId = 3

--GROUP BY productNodeId
) as x
group by id,name,quantity,duration,frequency,subscription,unitprice,weight

根据@Anthony Hancock 的评论,最简单的解决方案是将 CASE 条件语句包装在 SUM 聚合器中,如下所示:

SELECT 
  productNodeId AS id, 
  MAX(productName) AS name, 
  SUM(CASE   
    WHEN subscription = 1 THEN unitWeight*(duration/frequency)
  ELSE
    unitWeight*quantity
  END) AS weight,
  SUM(CASE   
    WHEN subscription = 1 THEN unitPrice*(duration/frequency)
  ELSE
    unitPrice*quantity
  END) AS total

FROM Order INNER JOIN OrderLine ON Order.id = OrderLine.orderId WHERE orderStatusId = 3
GROUP BY productNodeId
ORDER BY total DESC