将文件从 android 上传到服务器失败
Uploading file from android to server fails
我正在尝试将文件上传到服务器。我尝试通过两种方式做到这一点。
第一种方法
这是第一种方法的代码：
String lineEnd = "\r\n";
String twoHyphens = "--";
String boundary = "*****";
int bytesRead, bytesAvailable, bufferSize;
byte[] buffer;
int maxBufferSize = 1 * 1024 * 1024;
File sourceFile = new File(fileName);
try {
// open a URL connection to the Servlet
FileInputStream fileInputStream = new FileInputStream(sourceFile);
URL url = new URL("http://localhost:8000/cgi-bin/test.py?action=upload&code=123");
// Open a HTTP connection to the URL
conn = (HttpURLConnection) url.openConnection();
conn.setDoInput(true); // Allow Inputs
conn.setDoOutput(true); // Allow Outputs
conn.setUseCaches(false); // Don't use a Cached Copy
conn.setRequestMethod("POST");
conn.setRequestProperty("Connection", "Keep-Alive");
conn.setRequestProperty("ENCTYPE", "multipart/form-data");
conn.setRequestProperty("Content-Type", "multipart/form-data;boundary=" + boundary);
conn.setRequestProperty("file", fileName);
dos = new DataOutputStream(conn.getOutputStream());
dos.writeBytes(twoHyphens + boundary + lineEnd);
dos.writeBytes("Content-Disposition: form-data; name=\"file\";filename=\""
+ fileName + "\"" + lineEnd);
dos.writeBytes(lineEnd);
// create a buffer of maximum size
bytesAvailable = fileInputStream.available();
bufferSize = Math.min(bytesAvailable, maxBufferSize);
buffer = new byte[bufferSize];
// read file and write it into form...
bytesRead = fileInputStream.read(buffer, 0, bufferSize);
while (bytesRead > 0) {
dos.write(buffer, 0, bufferSize);
bytesAvailable = fileInputStream.available();
bufferSize = Math.min(bytesAvailable, maxBufferSize);
bytesRead = fileInputStream.read(buffer, 0, bufferSize);
}
// send multipart form data necesssary after file data...
dos.writeBytes(lineEnd);
dos.writeBytes(twoHyphens + boundary + twoHyphens + lineEnd);
// Responses from the server (code and message)
int serverResponseCode = conn.getResponseCode();
String serverResponseMessage = conn.getResponseMessage();
Log.i("uploadFile", "HTTP Response is : "
+ serverResponseMessage + ": " + serverResponseCode);
if(serverResponseCode == 200){
}
//close the streams //
fileInputStream.close();
dos.flush();
dos.close();
} catch (MalformedURLException ex) {
Log.e("Upload file to server", "error: " + ex.getMessage(), ex);
} catch (Exception e) {
Log.e("Upload file to server Exception", "Exception : "
+ e.getMessage(), e);
}
在int serverResponseCode = conn.getResponseCode();行代码抛出如下异常：
java.io.EOFException
at libcore.io.Streams.readAsciiLine(Streams.java:203)
at libcore.net.http.HttpEngine.readHeaders(HttpEngine.java:609)
at libcore.net.http.HttpEngine.readResponseHeaders(HttpEngine.java:562)
at libcore.net.http.HttpEngine.readResponse(HttpEngine.java:814)
at libcore.net.http.HttpURLConnectionImpl.getResponse(HttpURLConnectionImpl.java:293)
at libcore.net.http.HttpURLConnectionImpl.getResponseCode(HttpURLConnectionImpl.java:505)
at ir.fajrdev.uploader.HTTP.HTTPUploader.upload1(HTTPUploader.java:241)
at ir.fajrdev.uploader.HTTP.HTTPUploader.uploadAllFiles(HTTPUploader.java:48)
at ir.fajrdev.uploader.fragments.UploadFragment.run(UploadFragment.java:74)
at java.lang.Thread.run(Thread.java:856)
我已经搜索过这个异常，它似乎是一个错误，但没有一个答案对我有用。
第二种方法
所以我尝试了另一种方法，如下所示：
File file = new File(f.address);
HttpClient httpClient = new DefaultHttpClient();
HttpContext localContext = new BasicHttpContext();
HttpPost httpPost = new HttpPost("http://localhost:8000/cgi-bin/test.py?action=upload&code=123");
try {
MultipartEntityBuilder entityBuilder = MultipartEntityBuilder.create();
entityBuilder.setMode(HttpMultipartMode.BROWSER_COMPATIBLE);
FileBody fb = new FileBody(file);
entityBuilder.addPart("file", fb);
HttpEntity entity = entityBuilder.build();
httpPost.setEntity(entity);
HttpResponse response = httpClient.execute(httpPost, localContext);
String result = EntityUtils.toString(response.getEntity());
if ("done".equals(result)) {
DatabaseManager.sharedDB().fileUploaded(f.id);
}
} catch (IOException e) {
e.printStackTrace();
}
这里的问题是响应应该是 done 但它是一个空字符串。从服务器端登录后，它说没有属性 filename。服务器正在运行，因为我可以使用我之前编写的 iOS 应用程序上传文件，但我也不能在 android 应用程序上完成此操作。
我检查了两种方法中发送的数据，它们看起来很相似，除了第二种方法中有一行 Content-Type: application/octet-stream 在第一种方法输出中不存在。
抱歉问了这么长的问题:)
使用这个示例代码，它会工作正常
try {
// open a URL connection to the Servlet
FileInputStream fileInputStream = new FileInputStream(sourceFile);
URL url = new URL(upLoadServerUri);
// Open a HTTP connection to the URL
conn = (HttpURLConnection) url.openConnection();
conn.setDoInput(true); // Allow Inputs
conn.setDoOutput(true); // Allow Outputs
conn.setUseCaches(false); // Don't use a Cached Copy
conn.setRequestMethod("POST");
conn.setRequestProperty("Connection", "Keep-Alive");
conn.setRequestProperty("ENCTYPE", "multipart/form-data");
conn.setRequestProperty("Content-Type", "multipart/form-data;boundary=" + boundary);
conn.setRequestProperty("uploaded_file", fileName);
dos = new DataOutputStream(conn.getOutputStream());
dos.writeBytes(twoHyphens + boundary + lineEnd);
dos.writeBytes("Content-Disposition: form-data; name=\"uploaded_file\";filename=\""
+ fileName + "\"" + lineEnd);
dos.writeBytes(lineEnd);
// create a buffer of maximum size
bytesAvailable = fileInputStream.available();
bufferSize = Math.min(bytesAvailable, maxBufferSize);
buffer = new byte[bufferSize];
// read file and write it into form...
bytesRead = fileInputStream.read(buffer, 0, bufferSize);
while (bytesRead > 0) {
dos.write(buffer, 0, bufferSize);
bytesAvailable = fileInputStream.available();
bufferSize = Math.min(bytesAvailable, maxBufferSize);
bytesRead = fileInputStream.read(buffer, 0, bufferSize);
}
// send multipart form data necesssary after file data...
dos.writeBytes(lineEnd);
dos.writeBytes(twoHyphens + boundary + twoHyphens + lineEnd);
// Responses from the server (code and message)
serverResponseCode = conn.getResponseCode();
String serverResponseMessage = conn.getResponseMessage();
Log.i("uploadFile", "HTTP Response is : "
+ serverResponseMessage + ": " + serverResponseCode);
if(serverResponseCode == 200){
runOnUiThread(new Runnable() {
public void run() {
String msg = "File Upload Completed.\n\n See uploaded file here : \n\n"
+" http://www.androidexample.com/media/uploads/"
+uploadFileName;
messageText.setText(msg);
Toast.makeText(UploadToServer.this, "File Upload Complete.",
Toast.LENGTH_SHORT).show();
}
});
}
//close the streams //
fileInputStream.close();
dos.flush();
dos.close();
} catch (MalformedURLException ex) {
dialog.dismiss();
ex.printStackTrace();
runOnUiThread(new Runnable() {
public void run() {
messageText.setText("MalformedURLException Exception : check script url.");
Toast.makeText(UploadToServer.this, "MalformedURLException", Toast.LENGTH_SHORT).show();
}
});
Log.e("Upload file to server", "error: " + ex.getMessage(), ex);
} catch (Exception e) {
dialog.dismiss();
e.printStackTrace();
runOnUiThread(new Runnable() {
public void run() {
messageText.setText("Got Exception : see logcat ");
Toast.makeText(UploadToServer.this, "Got Exception : see logcat ",
Toast.LENGTH_SHORT).show();
}
});
Log.e("Upload file to server Exception", "Exception : "
+ e.getMessage(), e);
}
有一个愚蠢的问题:)
我的应用程序运行 NanoHttpd 服务器，我将文件上传到它。然后我有一个按钮可以将文件上传到网上的服务器。问题是我上传任何上传给我的东西！ （我没有把参数放在问题的代码中，这样会更容易找到解决方案）。 NanoHttpd 会为每个已上传的文件创建一个名为 file 的参数。因此，当我将所有这些参数上传到服务器时，它会看到 file 参数但没有文件名。所以我刚刚删除了 file 参数，现在第二种方法效果很好！
P.S: 还是第一种方法不行（题中的代码和答案中的代码都不行）。现在不知道为什么？！
我正在尝试将文件上传到服务器。我尝试通过两种方式做到这一点。
第一种方法
这是第一种方法的代码：
String lineEnd = "\r\n";
String twoHyphens = "--";
String boundary = "*****";
int bytesRead, bytesAvailable, bufferSize;
byte[] buffer;
int maxBufferSize = 1 * 1024 * 1024;
File sourceFile = new File(fileName);
try {
// open a URL connection to the Servlet
FileInputStream fileInputStream = new FileInputStream(sourceFile);
URL url = new URL("http://localhost:8000/cgi-bin/test.py?action=upload&code=123");
// Open a HTTP connection to the URL
conn = (HttpURLConnection) url.openConnection();
conn.setDoInput(true); // Allow Inputs
conn.setDoOutput(true); // Allow Outputs
conn.setUseCaches(false); // Don't use a Cached Copy
conn.setRequestMethod("POST");
conn.setRequestProperty("Connection", "Keep-Alive");
conn.setRequestProperty("ENCTYPE", "multipart/form-data");
conn.setRequestProperty("Content-Type", "multipart/form-data;boundary=" + boundary);
conn.setRequestProperty("file", fileName);
dos = new DataOutputStream(conn.getOutputStream());
dos.writeBytes(twoHyphens + boundary + lineEnd);
dos.writeBytes("Content-Disposition: form-data; name=\"file\";filename=\""
+ fileName + "\"" + lineEnd);
dos.writeBytes(lineEnd);
// create a buffer of maximum size
bytesAvailable = fileInputStream.available();
bufferSize = Math.min(bytesAvailable, maxBufferSize);
buffer = new byte[bufferSize];
// read file and write it into form...
bytesRead = fileInputStream.read(buffer, 0, bufferSize);
while (bytesRead > 0) {
dos.write(buffer, 0, bufferSize);
bytesAvailable = fileInputStream.available();
bufferSize = Math.min(bytesAvailable, maxBufferSize);
bytesRead = fileInputStream.read(buffer, 0, bufferSize);
}
// send multipart form data necesssary after file data...
dos.writeBytes(lineEnd);
dos.writeBytes(twoHyphens + boundary + twoHyphens + lineEnd);
// Responses from the server (code and message)
int serverResponseCode = conn.getResponseCode();
String serverResponseMessage = conn.getResponseMessage();
Log.i("uploadFile", "HTTP Response is : "
+ serverResponseMessage + ": " + serverResponseCode);
if(serverResponseCode == 200){
}
//close the streams //
fileInputStream.close();
dos.flush();
dos.close();
} catch (MalformedURLException ex) {
Log.e("Upload file to server", "error: " + ex.getMessage(), ex);
} catch (Exception e) {
Log.e("Upload file to server Exception", "Exception : "
+ e.getMessage(), e);
}
在int serverResponseCode = conn.getResponseCode();行代码抛出如下异常：
java.io.EOFException
at libcore.io.Streams.readAsciiLine(Streams.java:203)
at libcore.net.http.HttpEngine.readHeaders(HttpEngine.java:609)
at libcore.net.http.HttpEngine.readResponseHeaders(HttpEngine.java:562)
at libcore.net.http.HttpEngine.readResponse(HttpEngine.java:814)
at libcore.net.http.HttpURLConnectionImpl.getResponse(HttpURLConnectionImpl.java:293)
at libcore.net.http.HttpURLConnectionImpl.getResponseCode(HttpURLConnectionImpl.java:505)
at ir.fajrdev.uploader.HTTP.HTTPUploader.upload1(HTTPUploader.java:241)
at ir.fajrdev.uploader.HTTP.HTTPUploader.uploadAllFiles(HTTPUploader.java:48)
at ir.fajrdev.uploader.fragments.UploadFragment.run(UploadFragment.java:74)
at java.lang.Thread.run(Thread.java:856)
我已经搜索过这个异常，它似乎是一个错误，但没有一个答案对我有用。
第二种方法
所以我尝试了另一种方法，如下所示：
File file = new File(f.address);
HttpClient httpClient = new DefaultHttpClient();
HttpContext localContext = new BasicHttpContext();
HttpPost httpPost = new HttpPost("http://localhost:8000/cgi-bin/test.py?action=upload&code=123");
try {
MultipartEntityBuilder entityBuilder = MultipartEntityBuilder.create();
entityBuilder.setMode(HttpMultipartMode.BROWSER_COMPATIBLE);
FileBody fb = new FileBody(file);
entityBuilder.addPart("file", fb);
HttpEntity entity = entityBuilder.build();
httpPost.setEntity(entity);
HttpResponse response = httpClient.execute(httpPost, localContext);
String result = EntityUtils.toString(response.getEntity());
if ("done".equals(result)) {
DatabaseManager.sharedDB().fileUploaded(f.id);
}
} catch (IOException e) {
e.printStackTrace();
}
这里的问题是响应应该是 done 但它是一个空字符串。从服务器端登录后，它说没有属性 filename。服务器正在运行，因为我可以使用我之前编写的 iOS 应用程序上传文件，但我也不能在 android 应用程序上完成此操作。
我检查了两种方法中发送的数据，它们看起来很相似，除了第二种方法中有一行 Content-Type: application/octet-stream 在第一种方法输出中不存在。
抱歉问了这么长的问题:)
使用这个示例代码，它会工作正常
try {
// open a URL connection to the Servlet
FileInputStream fileInputStream = new FileInputStream(sourceFile);
URL url = new URL(upLoadServerUri);
// Open a HTTP connection to the URL
conn = (HttpURLConnection) url.openConnection();
conn.setDoInput(true); // Allow Inputs
conn.setDoOutput(true); // Allow Outputs
conn.setUseCaches(false); // Don't use a Cached Copy
conn.setRequestMethod("POST");
conn.setRequestProperty("Connection", "Keep-Alive");
conn.setRequestProperty("ENCTYPE", "multipart/form-data");
conn.setRequestProperty("Content-Type", "multipart/form-data;boundary=" + boundary);
conn.setRequestProperty("uploaded_file", fileName);
dos = new DataOutputStream(conn.getOutputStream());
dos.writeBytes(twoHyphens + boundary + lineEnd);
dos.writeBytes("Content-Disposition: form-data; name=\"uploaded_file\";filename=\""
+ fileName + "\"" + lineEnd);
dos.writeBytes(lineEnd);
// create a buffer of maximum size
bytesAvailable = fileInputStream.available();
bufferSize = Math.min(bytesAvailable, maxBufferSize);
buffer = new byte[bufferSize];
// read file and write it into form...
bytesRead = fileInputStream.read(buffer, 0, bufferSize);
while (bytesRead > 0) {
dos.write(buffer, 0, bufferSize);
bytesAvailable = fileInputStream.available();
bufferSize = Math.min(bytesAvailable, maxBufferSize);
bytesRead = fileInputStream.read(buffer, 0, bufferSize);
}
// send multipart form data necesssary after file data...
dos.writeBytes(lineEnd);
dos.writeBytes(twoHyphens + boundary + twoHyphens + lineEnd);
// Responses from the server (code and message)
serverResponseCode = conn.getResponseCode();
String serverResponseMessage = conn.getResponseMessage();
Log.i("uploadFile", "HTTP Response is : "
+ serverResponseMessage + ": " + serverResponseCode);
if(serverResponseCode == 200){
runOnUiThread(new Runnable() {
public void run() {
String msg = "File Upload Completed.\n\n See uploaded file here : \n\n"
+" http://www.androidexample.com/media/uploads/"
+uploadFileName;
messageText.setText(msg);
Toast.makeText(UploadToServer.this, "File Upload Complete.",
Toast.LENGTH_SHORT).show();
}
});
}
//close the streams //
fileInputStream.close();
dos.flush();
dos.close();
} catch (MalformedURLException ex) {
dialog.dismiss();
ex.printStackTrace();
runOnUiThread(new Runnable() {
public void run() {
messageText.setText("MalformedURLException Exception : check script url.");
Toast.makeText(UploadToServer.this, "MalformedURLException", Toast.LENGTH_SHORT).show();
}
});
Log.e("Upload file to server", "error: " + ex.getMessage(), ex);
} catch (Exception e) {
dialog.dismiss();
e.printStackTrace();
runOnUiThread(new Runnable() {
public void run() {
messageText.setText("Got Exception : see logcat ");
Toast.makeText(UploadToServer.this, "Got Exception : see logcat ",
Toast.LENGTH_SHORT).show();
}
});
Log.e("Upload file to server Exception", "Exception : "
+ e.getMessage(), e);
}
有一个愚蠢的问题:)
我的应用程序运行 NanoHttpd 服务器，我将文件上传到它。然后我有一个按钮可以将文件上传到网上的服务器。问题是我上传任何上传给我的东西！ （我没有把参数放在问题的代码中，这样会更容易找到解决方案）。 NanoHttpd 会为每个已上传的文件创建一个名为 file 的参数。因此，当我将所有这些参数上传到服务器时，它会看到 file 参数但没有文件名。所以我刚刚删除了 file 参数，现在第二种方法效果很好！
P.S: 还是第一种方法不行（题中的代码和答案中的代码都不行）。现在不知道为什么？！