Return 从函数提升 streambuf
Return boost streambuf from function
我正在尝试将读取 gz 文件的代码打包成一个函数,源代码取自 https://techoverflow.net/2013/11/03/c-iterating-lines-in-a-gz-file-using-boostiostreams/
我的尝试
boost::iostreams::filtering_streambuf<boost::iostreams::input> func(std::string filename);
boost::iostreams::filtering_streambuf<boost::iostreams::input> func(std::string filename)
{
std::ifstream file(filename, std::ios_base::in | std::ios_base::binary);
boost::iostreams::filtering_streambuf<boost::iostreams::input> inbuf;
inbuf.push(boost::iostreams::gzip_decompressor());
inbuf.push(file);
return inbuf;
}
void mymainfunc(std::string filename)
{
//Convert streambuf to istream
std::istream ifstrm( func( filename));
std::string line;
while(std::getline(ifstrm, line)) {
std::cout << line << std::endl;
}
}
代码 运行 如果不通过函数 运行 没问题,我认为我在 return 类型中做错了。
错误:https://pastebin.com/kFpjYG0M
流不可复制。其实这个filteringstreambuf是连动都动不了的
所以在这种情况下,您需要通过智能指针动态分配和return。然而,即使只是 returning 过滤 streambuf 也不起作用,因为它会保存对 ifstream 的引用。那是本地人。
所以,也许你需要打包它:
#include <boost/iostreams/filtering_streambuf.hpp>
#include <boost/iostreams/filter/gzip.hpp>
#include <fstream>
namespace bio = boost::iostreams;
struct MySource {
using fisb = bio::filtering_istreambuf;
struct State {
State(std::string filename) : ifs(filename, std::ios::binary) {
buf.push(bio::gzip_decompressor());
buf.push(ifs);
}
fisb buf;
std::ifstream ifs;
std::istream is { &buf };
};
std::unique_ptr<State> _state;
operator std::istream&() const { return _state->is; }
};
MySource func(std::string filename) {
auto inbuf = std::make_unique<MySource::State>(filename);
return {std::move(inbuf)};
}
#include <iostream>
void mymainfunc(std::string filename)
{
auto source = func(filename);
std::istream& is = source;
std::string line;
while(std::getline(is, line)) {
std::cout << line << std::endl;
}
}
int main(){
mymainfunc("test.cpp.gz");
}
选择 #1
你可以简化一下:
struct MySource {
struct State {
State(std::string filename) : ifs(filename, std::ios::binary) {
is.push(bio::gzip_decompressor());
is.push(ifs);
}
std::ifstream ifs;
bio::filtering_istream is;
};
std::unique_ptr<State> _state;
operator std::istream&() const { return _state->is; }
};
不单独处理流缓冲区使它更简单。
选择#2
不照抄自有其风采:
#include <boost/iostreams/filtering_stream.hpp>
#include <boost/iostreams/filter/gzip.hpp>
#include <fstream>
#include <iostream>
void mymainfunc(std::istream& is) {
std::string line;
while(std::getline(is, line)) {
std::cout << line << std::endl;
}
}
namespace bio = boost::iostreams;
int main(){
std::ifstream ifs("test.cpp.gz", std::ios::binary);
bio::filtering_istream is;
is.push(bio::gzip_decompressor());
is.push(ifs);
mymainfunc(is);
}
我正在尝试将读取 gz 文件的代码打包成一个函数,源代码取自 https://techoverflow.net/2013/11/03/c-iterating-lines-in-a-gz-file-using-boostiostreams/
我的尝试
boost::iostreams::filtering_streambuf<boost::iostreams::input> func(std::string filename);
boost::iostreams::filtering_streambuf<boost::iostreams::input> func(std::string filename)
{
std::ifstream file(filename, std::ios_base::in | std::ios_base::binary);
boost::iostreams::filtering_streambuf<boost::iostreams::input> inbuf;
inbuf.push(boost::iostreams::gzip_decompressor());
inbuf.push(file);
return inbuf;
}
void mymainfunc(std::string filename)
{
//Convert streambuf to istream
std::istream ifstrm( func( filename));
std::string line;
while(std::getline(ifstrm, line)) {
std::cout << line << std::endl;
}
}
代码 运行 如果不通过函数 运行 没问题,我认为我在 return 类型中做错了。 错误:https://pastebin.com/kFpjYG0M
流不可复制。其实这个filteringstreambuf是连动都动不了的
所以在这种情况下,您需要通过智能指针动态分配和return。然而,即使只是 returning 过滤 streambuf 也不起作用,因为它会保存对 ifstream 的引用。那是本地人。
所以,也许你需要打包它:
#include <boost/iostreams/filtering_streambuf.hpp>
#include <boost/iostreams/filter/gzip.hpp>
#include <fstream>
namespace bio = boost::iostreams;
struct MySource {
using fisb = bio::filtering_istreambuf;
struct State {
State(std::string filename) : ifs(filename, std::ios::binary) {
buf.push(bio::gzip_decompressor());
buf.push(ifs);
}
fisb buf;
std::ifstream ifs;
std::istream is { &buf };
};
std::unique_ptr<State> _state;
operator std::istream&() const { return _state->is; }
};
MySource func(std::string filename) {
auto inbuf = std::make_unique<MySource::State>(filename);
return {std::move(inbuf)};
}
#include <iostream>
void mymainfunc(std::string filename)
{
auto source = func(filename);
std::istream& is = source;
std::string line;
while(std::getline(is, line)) {
std::cout << line << std::endl;
}
}
int main(){
mymainfunc("test.cpp.gz");
}
选择 #1
你可以简化一下:
struct MySource {
struct State {
State(std::string filename) : ifs(filename, std::ios::binary) {
is.push(bio::gzip_decompressor());
is.push(ifs);
}
std::ifstream ifs;
bio::filtering_istream is;
};
std::unique_ptr<State> _state;
operator std::istream&() const { return _state->is; }
};
不单独处理流缓冲区使它更简单。
选择#2
不照抄自有其风采:
#include <boost/iostreams/filtering_stream.hpp>
#include <boost/iostreams/filter/gzip.hpp>
#include <fstream>
#include <iostream>
void mymainfunc(std::istream& is) {
std::string line;
while(std::getline(is, line)) {
std::cout << line << std::endl;
}
}
namespace bio = boost::iostreams;
int main(){
std::ifstream ifs("test.cpp.gz", std::ios::binary);
bio::filtering_istream is;
is.push(bio::gzip_decompressor());
is.push(ifs);
mymainfunc(is);
}