GridView，获取Item的父View

Question

我正在尝试通过单次触摸事件向 GridView 中的子元素发送点击。到目前为止，我可以检索子元素的数据，但无法对其执行点击。

让我再解释一下事物的布局...

GridView - 在此处触摸事件处理程序...
- LinearLayout - 这里的 onClick 侦听器...
  - TextView - 只是一些文本...

一个适配器用 LinearLayout 填充了 GridView，他们定义了 onClick 事件。这些布局包含 TextView，其中 TextView.setText("Some data from my dataset")

我有一个 onTouch 侦听器，它当前正在侦听 GridView 上的触摸事件，并且正在根据手指的位置成功找到 TextView 的数据。

如何获取TextView的父视图，并在用户手指位置调用performClick？

这是当前的点击处理程序，包含我目前所获得的... 假设 GridView & Adapter 已正确初始化...

@Override
        public boolean onTouch(View v, MotionEvent event) {
            int action = MotionEventCompat.getActionMasked(event);
            switch(action)
            {
            case (MotionEvent.ACTION_DOWN) :
            case (MotionEvent.ACTION_MOVE) :
                int position = GridView.pointToPosition((int)event.getX(),(int)event.getY());
                if (position != -1)
                {
                // I have looked at the other .get methods, and doing GridView.getXYZ (Where XYZ could be any method) and couldn't get anywhere...
                String item = Adapter.getItem(position);                    
                Log.d("TouchEvent","Action was DOWN/MOVE on " + item);
                return true;
                }
            case (MotionEvent.ACTION_UP) :
                Log.d("TouchEvent","Action was UP");
                return true;
            case (MotionEvent.ACTION_CANCEL) :
                Log.d("TouchEvent","Action was CANCEL");
                return true;
            case (MotionEvent.ACTION_OUTSIDE) :
                Log.d("TouchEvent","Movement occurred outside bounds " +
                        "of current screen element");
                return true;      
            default : 
                return true;
            }
        }
    });

谢谢！

还想提一下，这个 GridView 包含在一个片段中。我怀疑它会改变世界，但可能会影响你们的解决方案。

Answer 1

啊啊……我们需要尝试一下，

实现方法如

private View getViewByPosition(GridView gridView, int position) {
    int firstPosition = gridView.getFirstVisiblePosition();
    int lastPosition = gridView.getLastVisiblePosition();

    if ((position < firstPosition) || (position > lastPosition))
        return null;

    return gridView.getChildAt(position - firstPosition);
}

现在，调用这个方法，

if (position != -1)
{
    // I have looked at the other .get methods, and doing                  GridView.getXYZ (Where XYZ could be any method) and couldn't get anywhere...
    GridView gridView = (GridView) v;
    View touchedView = getViewByPosition(gridView, position);

    String item = Adapter.getItem(position);                    
    Log.d("TouchEvent","Action was DOWN/MOVE on " + item);
    return true;
}

Answer 2

试试这个

gridview.setOnItemClickListener(new OnItemClickListener() {
public void onItemClick(AdapterView parent, View v, int 位置，长 id）
{
// 将意图发送到 SingleViewActivity
Intent i = new Intent(getApplicationContext(), SingleViewActivity.class);
// 传递图像索引
i.putExtra("id",位置);
开始Activity(i);
}
});

在此之后创建 SingleViewActivity.java class

public class SingleViewActivity 扩展 Activity
{
@Override
public void onCreate(Bundle savedInstanceState)
{
super.onCreate(savedInstanceState);
setContentView(R.layout.single_view);

// 获取意图数据
Intent i = getIntent();
// 选中的图片id
int position = i.getExtras().getInt("id");
ImageAdapter imageAdapter = new ImageAdapter(this);
ImageView imageView = (ImageView) findViewById(R.id.SingleView); imageView.setImageResource(imageAdapter.mThumbIds[位置]);
}
}

GridView，获取Item的父View

GridView, Get Item's parent View

android

android-layout

android-view

android-adapter

android-gridview