无法正确反序列化 xml

Question

我要反序列化以下字符串：

<result>
<error>
    <errorcode>0</errorcode>
    <errorge>წარმატებით</errorge>
    <errorru>Удачно</errorru>
    <erroren>successfully</erroren>
    <line>89</line>
</error>
<amount>
    <gel>1</gel>
</amount>
<user>01001</user>
<service>MyService</service> // here
<data>
    <nickname>popcorn2</nickname>
    <identification_name>identified</identification_name>
    <wallet_code>5554654</wallet_code>
    <NationalRate>1</NationalRate>
    <RATE>1</RATE>
    <GENERATED_AMOUNT>1</GENERATED_AMOUNT>
    <CURRENCY>GEL</CURRENCY>
</data>
<accoutant>
    <agentBenefit>0</agentBenefit>
    <agentCommission>0.44</agentCommission>
    <clientCommission>0</clientCommission>
</accoutant>
<service>
    <min_amount>0.49</min_amount>
    <max_amount>1500.00</max_amount>
    <currency>GEL</currency>
</service>
<avance>-134206.1500</avance>
<operation_status>0</operation_status>
</result>

如您所见，它有两个名为 "service" 的标签，它们具有不同的内容

这是我一直在使用的 class

[XmlRoot(ElementName = "error")]
public class ErrorInfo
{
    [XmlElement(ElementName = "errorcode")]
    public string Errorcode { get; set; }
    [XmlElement(ElementName = "errorge")]
    public string Errorge { get; set; }
    [XmlElement(ElementName = "errorru")]
    public string Errorru { get; set; }
    [XmlElement(ElementName = "erroren")]
    public string Erroren { get; set; }
    [XmlElement(ElementName = "line")]
    public string Line { get; set; }
}

[XmlRoot(ElementName = "amount")]
public class Amount
{
    [XmlElement(ElementName = "gel")]
    public string Gel { get; set; }
}

[XmlRoot(ElementName = "data")]
public class Data
{
    [XmlElement(ElementName = "nickname")]
    public string Nickname { get; set; }
    [XmlElement(ElementName = "identification_name")]
    public string Identification_name { get; set; }
    [XmlElement(ElementName = "wallet_code")]
    public string Wallet_code { get; set; }
    [XmlElement(ElementName = "NationalRate")]
    public string NationalRate { get; set; }
    [XmlElement(ElementName = "RATE")]
    public string RATE { get; set; }
    [XmlElement(ElementName = "GENERATED_AMOUNT")]
    public string GENERATED_AMOUNT { get; set; }
    [XmlElement(ElementName = "CURRENCY")]
    public string CURRENCY { get; set; }
}

[XmlRoot(ElementName = "accoutant")]
public class Accoutant
{
    [XmlElement(ElementName = "agentBenefit")]
    public string AgentBenefit { get; set; }
    [XmlElement(ElementName = "agentCommission")]
    public string AgentCommission { get; set; }
    [XmlElement(ElementName = "clientCommission")]
    public string ClientCommission { get; set; }
}

[XmlRoot(ElementName = "service")]
public class Service
{
    [XmlElement(ElementName = "min_amount")]
    public string Min_amount { get; set; }
    [XmlElement(ElementName = "max_amount")]
    public string Max_amount { get; set; }
    [XmlElement(ElementName = "currency")]
    public string Currency { get; set; }
}

[XmlRoot(ElementName = "result")]
public class Result
{
    [XmlElement(ElementName = "error")]
    public ErrorInfo Error { get; set; }
    [XmlElement(ElementName = "amount")]
    public Amount Amount { get; set; }
    [XmlElement(ElementName = "user")]
    public string User { get; set; }
    [XmlElement(ElementName = "data")]
    public Data Data { get; set; }
    [XmlElement(ElementName = "accoutant")]
    public Accoutant Accoutant { get; set; }
    [XmlElement(ElementName = "service")]
    public Service[] Service { get; set; }
    [XmlElement(ElementName = "avance")]
    public string Avance { get; set; }
    [XmlElement(ElementName = "operation_status")]
    public string Operation_status { get; set; }
}

我尝试将服务标签作为数组处理，但无法正常工作。我能够从最后一个标签中获取值，但不能从第一个标签中获取值。这两个标签都是必需的，所以我想知道是否有办法从这两个标签中获取值？

Answer 1

不能有两个同名的不同元素。它不知道哪个标签属于哪里，您必须将名称更改为 "MyServiceName" 或类似的名称。

Answer 2

Visual Studio 有这个非常棒的功能，您可以将 XML 放入剪贴板，然后执行编辑 -> 选择性粘贴 -> 将 XML 粘贴为 class es.

如果您使用 XML 执行此操作，它会为服务标签生成以下 class：

/// <remarks/>
[System.SerializableAttribute()]
[System.ComponentModel.DesignerCategoryAttribute("code")]
[System.Xml.Serialization.XmlTypeAttribute(AnonymousType = true)]
public partial class resultService
{

     private decimal min_amountField;

     private decimal max_amountField;

     private string currencyField;

     private string[] textField;

     /// <remarks/>
     public decimal min_amount
     {
          get
          {
                return this.min_amountField;
          }
          set
          {
                this.min_amountField = value;
          }
     }

     /// <remarks/>
     public decimal max_amount
     {
          get
          {
                return this.max_amountField;
          }
          set
          {
                this.max_amountField = value;
          }
     }

     /// <remarks/>
     public string currency
     {
          get
          {
                return this.currencyField;
          }
          set
          {
                this.currencyField = value;
          }
     }

     /// <remarks/>
     [System.Xml.Serialization.XmlTextAttribute()]
     public string[] Text
     {
          get
          {
                return this.textField;
          }
          set
          {
                this.textField = value;
          }
     }
}

如果你想手动完成，秘诀似乎是添加一个带有 XmlTextAttribute 属性的字段。

Answer 3

按如下方式更改您的 classes：

[XmlRoot(ElementName = "result")]
public class Result
{
    // no need XmlElement attribute
    public ServiceComplex ServiceComplex { get; set; }

    // no need XmlElement attribute
    public string ServiceSimple { get; set; }

    // other properties
}

// no need XmlRoot attribute
public class ServiceComplex
{
    [XmlElement(ElementName = "min_amount")]
    public string Min_amount { get; set; }
    [XmlElement(ElementName = "max_amount")]
    public string Max_amount { get; set; }
    [XmlElement(ElementName = "currency")]
    public string Currency { get; set; }
}

而不是 ServiceComplex 和 ServiceSimple，选择适合您的名称。

订阅 XmlSerializer 到 UnknownElement 事件：

var xs = new XmlSerializer(typeof(Result));
xs.UnknownElement += Xs_UnknownElement;


private static void Xs_UnknownElement(object sender, XmlElementEventArgs e)
{
    if (e.Element.Name == "service")
    {
        var result = (Result)e.ObjectBeingDeserialized;
        if (e.Element.ChildNodes.Count == 1)
        {
            result.ServiceSimple = e.Element.InnerText;
        }
        else
        {
            result.ServiceComplex = new ServiceComplex
            {
                Min_amount = e.Element.SelectSingleNode("min_amount").InnerText,
                Max_amount = e.Element.SelectSingleNode("max_amount").InnerText,
                Currency = e.Element.SelectSingleNode("currency").InnerText
            };
        }
    }
}

在事件处理程序中，我们从 xml.

手动填充 class 的属性

无法正确反序列化 xml

Can't deserialize xml properly

c#

xml

xml-deserialization