使用 object 属性名称数组删除深度嵌套的 object 属性

Question

原标题：如何在实际object调用

之前动态地将属性包含在变量中

一般问题

如何创建 $target 才能正确 var_dumped？

    $type = 'lib';
    $target = 'test->test2';

    var_dump($GLOBALS[$this->context]->$type->test->test2);//returns object(test\test2)#15 (0) { } 

    var_dump($GLOBALS[$this->context]->$type->{$target}); //returns NULL ( Undefined property: stdClass::$test->test2 )

更多示例

这个（下图）很有魅力

   $target = 'test';
   $type = new \stdClass();
   $type->test = new \stdClass();
   $type->test->test2 = 5;
   var_dump($type->$target); // Returns object(stdClass)#24 (1) { ["test2"]=> int(5) }

这个（下）没有：

   $target = 'test->test2';
   $type = new \stdClass();
   $type->test = new \stdClass();
   $type->test->test2 = 5;
   var_dump($type->$target);// Returns NULL (Notice: Undefined property: stdClass::$test->test2)

真实案例：

我想取消设置$GLOBALS[$this->context]->$type->test->test2

我的第一个想法:

public function unSys($type, $thing) {

//$type = 'lib';
//$thing = 'test/test2';

$parts = explode('/',$thing);
$final = implode('->',$parts);
unset($GLOBALS[$this->context]->$type->{$final});

}

之后我尝试了什么：

...

$parts = explode('/',$thing);
$target = $GLOBALS[$this->context]->$type;

        foreach ($parts as $value) {
            $target = $target->$value;
        }

unset($target);
var_dump($GLOBALS[$this->context]->$type->test->test2);//still exist

...

我也试过通过引用传递但运气不好：

...
$target = &$GLOBALS[$this->context]->$type;
...

Answer 1

纪尧姆，

我认为您想要使用代表嵌套对象链的属性个名称的数组来删除最后一个嵌套对象属性。

看看这段代码是否有意义并能解决您的问题。

<?PHP

$GLOBALS['tmp'] = (object)array( 'lib' => (object)array( 'test' => (object)array( 'test2' => (object)array()) ) );
var_dump( $GLOBALS['tmp'] );

$context = 'tmp';

$type = 'lib';
$thing = 'test/test2';

$parts = explode('/',$thing);
$target = $GLOBALS[$context]->$type;
var_dump( $target );
var_dump( $parts );
$itemToUnset = array_pop( $parts );

foreach ($parts as &$value) {
    $target =& $target->$value;
}

unset( $target->{$itemToUnset} );
var_dump( $GLOBALS['tmp'] );

// test 2 is not set
var_dump( $GLOBALS['tmp']->lib->test->test2 );

输出如下所示：

object(stdClass)[4]
public 'lib' => 
    object(stdClass)[3]
        public 'test' => 
          object(stdClass)[2]
            public 'test2' => 
              object(stdClass)[1]
                ...
object(stdClass)[3]
public 'test' => 
    object(stdClass)[2]
        public 'test2' => 
        object(stdClass)[1]

array (size=2)
0 => string 'test' (length=4)
1 => string 'test2' (length=5)

object(stdClass)[4]
public 'lib' => 
    object(stdClass)[3]
        public 'test' => &
        object(stdClass)[2]

Notice: Undefined property: stdClass::$test2

使用 object 属性名称数组删除深度嵌套的 object 属性

Removing a deeply nested object property using an array of object property names

php

dynamic

stdclass

输出如下所示：

使用 object 属性 名称数组删除深度嵌套的 object 属性

Removing a deeply nested object property using an array of object property names

php

dynamic

stdclass

输出如下所示：

使用 object 属性名称数组删除深度嵌套的 object 属性