使用全文搜索以通过 laravel 查询生成器查找部分单词

Question

我想编写使用提供的短语搜索 table、return 匹配短语任何部分的值的搜索查询。这段代码有效，但结果一无所获。比如table有'abcde'，我搜索了'bcd'，结果没有。

protected function fullTextWildcards($term)
{
    return str_replace(' ', '*', $term) . '*';
}

public function index(Request $request, $slug = null)
{
    $query = $slug
        ? \App\Tag::whereSlug($slug)->firstOrFail()->articles()
        : new \App\Article;
    if ($keyword = request()->input('q')) {
        $raw = 'MATCH(title,content) AGAINST(? IN BOOLEAN MODE)';
        $query = $query->whereRaw($raw, [$this->fullTextWildcards($keyword)]);
    }

    $articles=$query->latest()->paginate(10);
    return view('articles.index',compact('articles'));
}

如何将所有内容链接在一起以达到预期的结果？
提前致谢。

Answer 1

您只需在查询中使用 like 即可获得给定列中的任何匹配项。试试这个：

public function index(Request $request, $slug = null)
{
  $filter = ['keyword' => $request->q , 'slug' => $slug];

  $articles = \App\Tag::where(function ($q) use ($filter){

    //you can leave this I just put the so the code seems clean
    if ($filter['slug'] !== null) {
      $q->whereSlug($slug);
    }

    if ($filter['keyword']) {

      $keyword  = $this->fullTextWildcards($filter['keyword']);

      //you can use **like** this
      $q->where('title', 'like', "%".$keyword."%")->orWhere('content', 'like',  "%".$keyword."%");
    }

  })->latest()->paginate(10);


  return view('articles.index',compact('articles'));

}

希望对您有所帮助

使用全文搜索以通过 laravel 查询生成器查找部分单词

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