计算数字重复次数的简单程序

Question

我完全是初学者python 3. 我遇到了一个问题。三颗星内请看代码：

s = input("Enter the value of N A B with white space in between ")
N, A, B=list(s.split())

def input_for_faces(*args):
    NumberOfA=0
    NumberOfB=0
    for x in args:
        if x == int(A):
            NumberOfA += 1
    for y in args:
        if y == int(B):
            NumberOfB += 1
    listAB=[NumberOfA, NumberOfB]
    return listAB

# ***
var=input("Enter the values on the faces of the cube seperated by commas ")
NA, NB=input_for_faces(var)
print(input_for_faces(var))
# ***

print("The probability of the chef winning is "+str((int(NA)/int(N)*(int(NB)/int(N))))

这种 *args 的输入方法没有给出正确的输出（它有效但给出了错误的答案）。但是当我为 args 直接赋值时，程序运行正常。

直接输入指的是：

s = input("Enter the value of N A B with white space in between ")
N, A, B=list(s.split())

def input_for_faces(*args):
    NumberOfA=0
    NumberOfB=0
    for x in args:
        if x == int(A):
            NumberOfA += 1
    for y in args:
        if y == int(B):
            NumberOfB += 1
    listAB=[NumberOfA, NumberOfB]
    return listAB

# ***
NA, NB=input_for_faces(1,1,1,1,1)
# ***

print("The probability of the chef winning is "+str((int(NA)/int(N))*(int(NB)/int(N))))

请告诉我我做错了什么。

Answer 1

1，在这部分的代码中，在 'if' 条件中，您将字符串与整数进行比较，这样条件将变为假并且不计算 'NumberOfA'

for x in args:
        if x == int(A):
            NumberOfA += 1
    for y in args:
        if y == int(B):
            NumberOfB += 1
    listAB=[NumberOfA, NumberOfB]

输出：

Enter the value of N A B with white space in between 1 1 1
Enter the values on the faces of the cube seperated by commas 1,1,1,1,1
[0, 0]
The probability of the chef winning is 0.0
>>>

2，您正在传递单个字符串作为 *args 的输入所以要传递多个参数，您必须将输入转换为列表 lvar=var.split(',') 然后使用 *lvar函数调用 {NA, NB=input_for_faces(*lvar)}, 将从列表

中一一传递多个参数

s = 输入("Enter the value of N A B with white space in between ") N、A、B=列表(s.split())

def input_for_faces(*args):
    NumberOfA=0
    NumberOfB=0
    for x in args:
        if x == A:
            NumberOfA += 1
    for y in args:
        if y == B:
            NumberOfB += 1
    listAB=[NumberOfA, NumberOfB]
    return listAB

# ***
var=input("Enter the values on the faces of the cube seperated by commas ")
lvar=var.split(',')
NA, NB=input_for_faces(*lvar)
print(input_for_faces(*lvar))
# ***

print("The probability of the chef winning is "+str((int(NA)/int(N)*(int(NB)/int(N)))))

输出：

Enter the value of N A B with white space in between 1 1 1
Enter the values on the faces of the cube seperated by commas 1,1,1,1,1
[5, 5]
The probability of the chef winning is 25.0

Answer 2

如果您不想或不必使用 *args，您可以这样做：

s = raw_input("Enter the value of N A B with white space in between ")
N, A, B=list(s.split())

def input_for_faces(inputList):
    NumberOfA=0
    NumberOfB=0
#You only need to loop through once for A and B, no need to do each separately
#You can still use the old one though if you want to
    for number in inputList:
        if number == int(A):
            NumberOfA += 1
        if number == int(B):
            NumberOfB += 1
    listAB =[NumberOfA, NumberOfB]
    return listAB

var =raw_input("Enter the values on the faces of the cube seperated by commas: ").split(",")
inputList = [int(i) for i in var]
NA,NB = input_for_faces(inputList)
print(input_for_faces(inputList))
print("The probability of the chef winning is "+str((int(NA)/int(N))*(int(NB)/int(N))))

或者如果您使用*args:

s = raw_input("Enter the value of N A B with white space in between ")
N, A, B=list(s.split())

def input_for_faces(*args):
    NumberOfA=0
    NumberOfB=0
#You only need to loop through once for A and B, no need to do each separately
#You can still use the old one though if you want to
    for number in inputList:
        if number == int(A):
            NumberOfA += 1
        if number == int(B):
            NumberOfB += 1
    listAB =[NumberOfA, NumberOfB]
    return listAB

var =raw_input("Enter the values on the faces of the cube seperated by commas: ").split(",")
inputList = [int(i) for i in var]
NA,NB = input_for_faces(*inputList)
print(input_for_faces(*inputList))
print("The probability of the chef winning is "+str((int(NA)/int(N))*(int(NB)/int(N))))

计算数字重复次数的简单程序

Simple program for counting number of repetition of a number

python

python-3.x

function

input

args