从循环中生成的字符串中删除最后一个字符

Question

相信我，我已经尝试了堆栈溢出中的所有方法！

所以，我得到了这个 JSON -

$j={
    "itempicture": [
        {
            "status": "3"
        },
        {
            "ItemCode": "001",
            "ItemImage": "image1",
            "ItemCategory": "shirt",
            "ShowOnPOS": "Yes",
            "LastModifiedOn": "2018-06-02 11:53:57"
        },
        {
            "ItemCode": "002",
            "ItemImage": "image2",
            "ItemCategory": "shirt",
            "ShowOnPOS": "Yes",
            "LastModifiedOn": "2018-06-02 11:53:57"
        }
    ]
}

我是这样访问它的 -

$jo = json_decode($j);
for($i = 1; $i < count($jo->itempicture); $i++) {
    foreach($jo->itempicture[$i] as $prop=>$val) {
        echo $val.",";
    }
    echo '<br>';
}

我得到了这个输出 -

001,image1,shirt,Yes,2018-06-02 11:53:57,
002,image2,shirt,Yes,2018-06-02 11:53:57,

这个输出的主要问题是最后的“,”。我无法删除它！

什么都试过了 - 这个 - Remove the last character from string

带有 substr、rtrim、内爆... 一切！

没用！

Answer 1

你可以这样做

 $jo=json_decode($j);

 for($i=1;$i<count($jo->itempicture);$i++){
 foreach($jo->itempicture[$i] as $prop=>$val){
      if ($value === end($jo->itempicture[$i])) {
        echo $val;
      }
      else {
        echo $val.",";
      }
 }
 echo '<br>';
}

通过比较当前迭代是否是循环的末尾，可以防止写入最后一个“,”

Answer 2

这是解决方案

$j='{"itempicture":[
{
    "status":"3"
},
{
    "ItemCode":"001",
    "ItemImage":"image1",
    "ItemCategory":"shirt",
    "ShowOnPOS":"Yes",
    "LastModifiedOn":"2018-06-02 11:53:57"
},
{
    "ItemCode":"002",
    "ItemImage":"image2",
    "ItemCategory":"shirt",
    "ShowOnPOS":"Yes",
    "LastModifiedOn":"2018-06-02 11:53:57"
}
]
}';
$jo=json_decode($j);
$edata = '';
for($i=1;$i<count($jo->itempicture);$i++){
    $data = '';
    foreach($jo->itempicture[$i] as $prop=>$val){
        $data .= $val.",";
    }
    $edata .= rtrim($data, ",");
    $edata .='<br/>';
}

echo "<pre>";
print_r($edata);
echo "</pre>";

Answer 3

如果你知道最后一个元素总是 LastModifiedOn

$jo=json_decode($j);
 for($i=1;$i<count($jo->itempicture);$i++){
 foreach($jo->itempicture[$i] as $prop=>$val){
    if($prop == "LastModifiedOn")
        echo $val;
    else
        echo $val.",";
 }
 echo '<br>';
}

Answer 4

一个使用implode()的版本，这意味着你必须从JSON转换成数组（默认是转换成对象，所以将true作为第二个参数添加到json_decode()） .

$j='{"itempicture":[
{
    "status":"3"
},
{
    "ItemCode":"001",
    "ItemImage":"image1",
    "ItemCategory":"shirt",
    "ShowOnPOS":"Yes",
    "LastModifiedOn":"2018-06-02 11:53:57"
},
{
    "ItemCode":"002",
    "ItemImage":"image2",
    "ItemCategory":"shirt",
    "ShowOnPOS":"Yes",
    "LastModifiedOn":"2018-06-02 11:53:57"
}
]
}';
$jo=json_decode($j, true);
array_shift($jo['itempicture']);
$edata = '';
foreach ( $jo['itempicture'] as $item)  {
    $edata .= implode(",", $item).'<br/>';
}
echo "<pre>";
print_r($edata);
echo "</pre>";

打印出来...

<pre>001,image1,shirt,Yes,2018-06-02 11:53:57<br/>
002,image2,shirt,Yes,2018-06-02 11:53:57<br/></pre>

从循环中生成的字符串中删除最后一个字符

Remove the last charater from string which is generated in loop

php

json

loops

trim

character-trimming