VSCode launch.json 中的动态进程 ID

Question

现在我的 launch.json 调试文件看起来像这样

{
   // ${command:pickProcess}
   "version": "0.2.0",
   "configurations": 
    [{ 
        "name": "(gdb) Attach",
        "type": "cppdbg",
        "request": "attach",
        "program": "${workspaceFolder}/devel/lib/beginner_tutorials/talker",
        "processId": "619",
        "MIMode": "gdb",
        "setupCommands": [
            {
                "description": "Enable pretty-printing for gdb",
                "text": "-enable-pretty-printing",
                "ignoreFailures": true
            }
        ]
    }
]}

但问题是我每次都需要手动更新 processid，对于 "processId"，我是否可以以编程方式调用某种脚本和 return pid ？前任。 "processId"：${shell_script：get_pid}

Answer 1

您可以使用 "processId": "${command:pickRemoteProcess}", 打开进程选择器，这样您就可以 select 它。

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