在 Scala 中设置隐式函数 return

Question

我正在编写 DSL（我的代码的领域特定语言）。代码是：

class NeuronGroupDSL(identifier: String)(implicit network: N2S3SimulationDSL ) // declared values which must be provided by the user, [we can just give a default constructor to this]
 {
  implicit val sizeDefault : Int = 28 // added the implicit default value for the setNumberOfNeurons method
  val id: String = identifier // We can add a default constructor with the Id and the network to this too allow user to skip this part
  var neuronGroup: Option[NeuronGroupRef] = None // this variable stores all the information by using the get property and a associated function with it
  private var neuronParameters: Seq[(Property[_], _)] = Seq()
  private var neuronModel: NeuronModel = _

/**Properties of the NeuronGroupDSL **/
// Added a default size to the size variable
  def ofSize(implicit size: Int): NeuronGroupDSL = {
    this.neuronGroup.get.setNumberOfNeurons(size)
    this
  }
// Give user the opportunity to choose the type of available models by the help of pattern matching
/**Neuron Model:
1. Linear leaky integrate-and-fire model
2. FitzHugh-Nagumo model
3. Izhikevich model
**/
  def modeling(model: NeuronModel): NeuronGroupDSL = {
    this.neuronModel = model
    this.neuronGroup.get.setNeuronModel(model, this.neuronParameters)
    this
  }
//we can define a default property the neuron group model here
  def withParameters(properties: (Property[_], _)*): NeuronGroupDSL = {
    this.neuronParameters = properties
    this.neuronGroup.get.setNeuronModel(this.neuronModel, properties)
    this
  }
}

如您所见定义 ofSize modeling withParameters 具有相同的 return 类型，因此是否可以隐式定义它们的 return 类型并在没有 return 部分的情况下定义这些函数？

请帮助我，我想尽可能地减少代码。

我也想知道是否可以在此代码中使用 case class 、 concise lambda syntax 以进一步最小化它。

Answer 1

您可以简单地删除 return 类型，它将自动推断：

def ofSize(implicit size: Int) = {
  neuronGroup.get.setNumberOfNeurons(size)
  this
}

在 Scala 中设置隐式函数 return

Set an implicit function return in Scala

dsl

scala