从点创建多线，使用 sf 包按 ID 分组

Question

我有一个积分集合，有一个 LINEID 和一个 ID_SEQ。 LINEID决定了唯一的Line-IDS，而ID_SEQ决定了点在Line-ID中的顺序。

我想将 点转换为按 ID_SEQ 排序并按 LINEID 分组的线。

使用包 sp，我能够达到预期的效果，但我想使用 sf 包来实现。我在这里错过了什么？

这里是一些虚拟数据，用 sp 函数说明了期望的结果，并且两次尝试用 sf 做同样的事情，但图表显示不同的结果。

library(sp)
library(sf)

sfpoints <- {
structure(list(LINEID = c(4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 
4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 10L, 10L, 
10L), ID_SEQ = c(10L, 11L, 12L, 13L, 16L, 30L, 31L, 32L, 33L, 
34L, 35L, 36L, 37L, 38L, 39L, 40L, 41L, 42L, 43L, 44L, 45L, 46L, 
1L, 2L, 3L), geometry = structure(list(structure(c(15.423568, 
47.06248), class = c("XY", "POINT", "sfg")), structure(c(15.423644, 
47.062523), class = c("XY", "POINT", "sfg")), structure(c(15.423691, 
47.062553), class = c("XY", "POINT", "sfg")), structure(c(15.423712, 
47.06257), class = c("XY", "POINT", "sfg")), structure(c(15.423716, 
47.062576), class = c("XY", "POINT", "sfg")), structure(c(15.423712, 
47.062588), class = c("XY", "POINT", "sfg")), structure(c(15.423731, 
47.062595), class = c("XY", "POINT", "sfg")), structure(c(15.423779, 
47.062626), class = c("XY", "POINT", "sfg")), structure(c(15.423835, 
47.062664), class = c("XY", "POINT", "sfg")), structure(c(15.423879, 
47.062714), class = c("XY", "POINT", "sfg")), structure(c(15.423897, 
47.062767), class = c("XY", "POINT", "sfg")), structure(c(15.423862, 
47.062828), class = c("XY", "POINT", "sfg")), structure(c(15.423783, 
47.062897), class = c("XY", "POINT", "sfg")), structure(c(15.423681, 
47.062973), class = c("XY", "POINT", "sfg")), structure(c(15.423564, 
47.06306), class = c("XY", "POINT", "sfg")), structure(c(15.423437, 
47.063164), class = c("XY", "POINT", "sfg")), structure(c(15.42331, 
47.06327), class = c("XY", "POINT", "sfg")), structure(c(15.423186, 
47.063385), class = c("XY", "POINT", "sfg")), structure(c(15.423062, 
47.063496), class = c("XY", "POINT", "sfg")), structure(c(15.422941, 
47.063602), class = c("XY", "POINT", "sfg")), structure(c(15.422821, 
47.063717), class = c("XY", "POINT", "sfg")), structure(c(15.422699, 
47.063824), class = c("XY", "POINT", "sfg")), structure(c(15.422518, 
47.061687), class = c("XY", "POINT", "sfg")), structure(c(15.422617, 
47.06179), class = c("XY", "POINT", "sfg")), structure(c(15.422717, 
47.061893), class = c("XY", "POINT", "sfg"))), class = c("sfc_POINT", 
"sfc"), precision = 0, bbox = structure(c(15.422518, 47.061687, 
15.423897, 47.063824), .Names = c("xmin", "ymin", "xmax", "ymax"
), class = "bbox"), crs = structure(list(epsg = NA_integer_, 
proj4string = NA_character_), .Names = c("epsg", "proj4string"
), class = "crs"), n_empty = 0L)), .Names = c("LINEID", "ID_SEQ", 
"geometry"), row.names = c(NA, -25L), class = c("sf", "data.frame"
), sf_column = "geometry", agr = structure(c(NA_integer_, NA_integer_
), .Names = c("LINEID", "ID_SEQ"), .Label = c("constant", "aggregate", 
"identity"), class = "factor"))}

par(mfrow=c(1,3))

## SP - way
tstssp <- as(sfpoints, "Spatial")
tstssp <- SpatialLines(lapply(split(tstssp, tstssp$LINEID), function(x) 
  Lines(list(Line(coordinates(x))), x$LINEID[1L])))
plot(tstssp, col=1:2, lwd=3, main="SP-Desired Result")


## SF - way ???
tst <- sfpoints %>% 
  group_by(LINEID) %>% 
  st_coordinates() %>%
  st_linestring()
plot(st_geometry(tst), col=1:2 , main="SF-Wrong Result")

tst <- sfpoints %>% 
  group_by(LINEID) %>%
  summarise() %>%
  st_cast("LINESTRING")
plot(st_geometry(tst), col=1:2, main="SF-Wrong Result")

Answer 1

正如 Edzer 在 this issue 中解释的那样，您必须为 summarise 函数提供参数 do_union = FALSE:

tst <- sfpoints %>% 
  group_by(LINEID) %>%
  summarise(do_union = FALSE) %>%
  st_cast("LINESTRING")
plot(st_geometry(tst), col=1:2)

从点创建多线，使用 sf 包按 ID 分组

Create Multilines from Points, grouped by ID with sf package

r

casting

sf