OSMnx 获取干净交叉点的 Lat Lon 坐标

Question

我正在使用 OSMnx 从 OpenStreetMaps 道路网络中获取 clean 交叉路口。交点节点当前位于 (x,y) 坐标中，但我想使用经纬度坐标绘制它们。

从示例 Jupiter 笔记本 OSMnx Example #14 Clean Intersection Cluster Nodes，我能够获取街道网络并调用 ox.clean_intersections 生成干净的交叉路口。

import osmnx as ox, matplotlib.pyplot as plt, numpy as np
ox.config(use_cache=True, log_console=True)
%matplotlib inline

# get a street network and plot it with all edge intersections
address = '2700 Shattuck Ave, Berkeley, CA'
G = ox.graph_from_address(address, network_type='drive', distance=750)
G_proj = ox.project_graph(G)

# clean up the intersections and extract their xy coords
intersections = ox.clean_intersections(G_proj, tolerance=15, dead_ends=False)
 points = np.array([point.xy for point in intersections])

我得到了交叉点的 Panda Geoseries，如下所示：

0       POINT (564152.437121744 4189596.945341664)
1      POINT (564846.6779513165 4189615.534235776)
2      POINT (564571.2116373706 4189601.780093061)

由于干净的交叉点由 centroids of clusters of merged nodes 组成，因此它们不对应于具有 osm_id（具有经纬度坐标）的任何特定节点。

如何将这些 (x,y) 点转换为经纬度坐标？

Answer 1

您将图形投影到米以使用合理的公差参数清理交叉点。现在你只需要将清理过的交叉点质心投影回经纬度：

import geopandas as gpd
gdf = gpd.GeoDataFrame(geometry=intersections)
gdf.crs = G_proj.graph['crs']
ox.project_gdf(gdf, to_latlong=True)

OSMnx 获取干净交叉点的 Lat Lon 坐标

OSMnx Get Lat Lon Coordinates of Clean Intersection Nodes

python

graph

openstreetmap

osmnx