函数 getUTCDate() returns 一个月
Function getUTCDate() returns a month
我有代码(19是日,6是月)
var dateObj = new Date("19.6.2018");
var month = dateObj.getUTCMonth() + 1; //months from 1-12
var day = dateObj.getUTCDate();
var year = dateObj.getUTCFullYear();
newdate = day + '.' + month + '.' + year;
alert(newdate);
此代码returnsNaN.NaN.NaN
函数 getUTCDate() returns 一个月。不知道为什么。
我是斯洛伐克人。第一个数字是日期。第二个数字是一个月。
Date
的 dateString 参数必须采用 Date.parse()
可识别的格式
String value representing a date. The string should be in a format
recognized by the Date.parse() method (IETF-compliant RFC 2822
timestamps and also a version of ISO8601).
日期时间字符串可能采用简化的 ISO 8601 格式。例如,“2011-10-10”
你的情况可以是
var dateObj = new Date("2018-06-19");
var month = dateObj.getUTCMonth() + 1; //months from 1-12
var day = dateObj.getUTCDate();
var year = dateObj.getUTCFullYear();
newdate = day + '.' + month + '.' + year;
console.log(newdate);
你可以像
一样使用你的字符串并正确格式化它
const str = "19.6.2018"
const arr = str.split('.');
const newString = `${arr[1]}-${arr[0]}-${arr[2]}`;
console.log(newString)
var dateObj = new Date(newString);
console.log(dateObj)
var month = dateObj.getUTCMonth() + 1; //months from 1-12
var day = dateObj.getUTCDate();
var year = dateObj.getUTCFullYear();
newdate = day + '.' + month + '.' + year;
alert(newdate);
除了@Shubham Khatri 的回答之外,您还可以通过以下方式将输入转换为正确的格式:
const getUTCDate = (year, month, day ) => {
const date = new Date(`${year}-${month}-${day}`);
const m = date.getUTCMonth() + 1; //months from 1-12
const d = date.getUTCDate();
const y = date.getUTCFullYear();
return [m, d, y]
}
const input = '19.6.2018'
const date = input.split('.')
// Here we convert your input, in the correct order `getUTCDate` expected
const result = getUTCDate(date[2], date[1], date[0])
console.log(result)
我有代码(19是日,6是月)
var dateObj = new Date("19.6.2018");
var month = dateObj.getUTCMonth() + 1; //months from 1-12
var day = dateObj.getUTCDate();
var year = dateObj.getUTCFullYear();
newdate = day + '.' + month + '.' + year;
alert(newdate);
此代码returnsNaN.NaN.NaN
函数 getUTCDate() returns 一个月。不知道为什么。
我是斯洛伐克人。第一个数字是日期。第二个数字是一个月。
Date
的 dateString 参数必须采用 Date.parse()
String value representing a date. The string should be in a format recognized by the Date.parse() method (IETF-compliant RFC 2822 timestamps and also a version of ISO8601).
日期时间字符串可能采用简化的 ISO 8601 格式。例如,“2011-10-10”
你的情况可以是
var dateObj = new Date("2018-06-19");
var month = dateObj.getUTCMonth() + 1; //months from 1-12
var day = dateObj.getUTCDate();
var year = dateObj.getUTCFullYear();
newdate = day + '.' + month + '.' + year;
console.log(newdate);
你可以像
一样使用你的字符串并正确格式化它const str = "19.6.2018"
const arr = str.split('.');
const newString = `${arr[1]}-${arr[0]}-${arr[2]}`;
console.log(newString)
var dateObj = new Date(newString);
console.log(dateObj)
var month = dateObj.getUTCMonth() + 1; //months from 1-12
var day = dateObj.getUTCDate();
var year = dateObj.getUTCFullYear();
newdate = day + '.' + month + '.' + year;
alert(newdate);
除了@Shubham Khatri 的回答之外,您还可以通过以下方式将输入转换为正确的格式:
const getUTCDate = (year, month, day ) => {
const date = new Date(`${year}-${month}-${day}`);
const m = date.getUTCMonth() + 1; //months from 1-12
const d = date.getUTCDate();
const y = date.getUTCFullYear();
return [m, d, y]
}
const input = '19.6.2018'
const date = input.split('.')
// Here we convert your input, in the correct order `getUTCDate` expected
const result = getUTCDate(date[2], date[1], date[0])
console.log(result)