二级子查询嵌套导致未知列

Question

我想根据给定用户与其他用户相比获得多少分来检索用户的排名（简单地计算比给定用户拥有更多分的用户）。

然而，在我尝试过的所有查询中，我总是以 Column not found: users.id 结束。据我所知，引用相关父列的级别超过一级是有限制的。

我可以重构我的查询，还是我真的需要使用 SET @rownum := 0 查询风格？

SELECT 
    `users`.*, 
    (
        SELECT COUNT(*) + 1 
        FROM (
            SELECT SUM(`amount`) AS `all_points` 
            FROM `points` 
            WHERE `type` = ? 
            GROUP BY `user_id` 
            HAVING `all_points` > (
                SELECT SUM(`amount`) 
                FROM `points` 
                WHERE `type` = ? and `user_id` = `users`.`id`
            )
        ) `points_sub`
    ) as `rank` 
FROM `users` 
WHERE `users`.`id` = ? 
LIMIT 1

Answer 1

我认为以下查询应该适合您。您可以在两个参数中传递要计算其排名的用户的 user_id。

SELECT 
`users`.*, 
(
    SELECT COUNT(*) + 1 
    FROM (
        SELECT SUM(`amount`) AS `all_points` 
        FROM `points` 
        WHERE `type` = ? 
        GROUP BY `user_id` 
        HAVING `all_points` > (
            SELECT COALESCE(SUM(`amount`),0) 
            FROM `points` 
            WHERE `type` = ? and `user_id` = ?
        )
    ) `points_sub`
) as `rank` 
FROM `users` 
WHERE `users`.`id` = ? 
LIMIT 1

Answer 2

您可以将子句上移一级，删除 having 过滤器并使用 where 过滤器

SELECT 
    `users`.*, 
    (
        SELECT COUNT(*) + 1 
        FROM (
            SELECT user_id,SUM(`amount`) AS `all_points` 
            FROM `points` 
            WHERE `type` = ? 
            GROUP BY `user_id` 
        ) `points_sub`
        WHERE `all_points` > 
                SELECT SUM(`amount`) 
                FROM `points` 
                WHERE `type` = ? and `user_id` = `users`.`id`

    ) as `rank` 
FROM `users` 
WHERE `users`.`id` = ?
LIMIT 1

二级子查询嵌套导致未知列

Unknown column due to second-level subquery nesting

mysql

sql

subquery

correlated-subquery