SQL 将多个记录中的值合并到一个列中的查询

Question

在我的 table 中，每条记录最多可以有 30 个不同的预算代码。我需要一个查询 returns table 中的所有预算代码作为单个列。查询我有错误指出子查询返回超过 1 个值。

SELECT 
        (SELECT [budgetCode1] FROM TABLE_NAME),
        (SELECT [budgetCode2] FROM TABLE_NAME),
        (SELECT [budgetCode3] FROM TABLE_NAME),
        (SELECT [budgetCode4] FROM TABLE_NAME),
        (SELECT [budgetCode5] FROM TABLE_NAME),
        (SELECT [budgetCode6] FROM TABLE_NAME),
        (SELECT [budgetCode7] FROM TABLE_NAME),
        (SELECT [budgetCode8] FROM TABLE_NAME),
        (SELECT [budgetCode9] FROM TABLE_NAME),
        (SELECT [budgetCode10] FROM TABLE_NAME),
        (SELECT [budgetCode11] FROM TABLE_NAME),
        (SELECT [budgetCode12] FROM TABLE_NAME),
        (SELECT [budgetCode13] FROM TABLE_NAME),
        (SELECT [budgetCode14] FROM TABLE_NAME),
        (SELECT [budgetCode15] FROM TABLE_NAME),
        (SELECT [budgetCode16] FROM TABLE_NAME),
        (SELECT [budgetCode17] FROM TABLE_NAME),
        (SELECT [budgetCode18] FROM TABLE_NAME),
        (SELECT [budgetCode19] FROM TABLE_NAME),
        (SELECT [budgetCode20] FROM TABLE_NAME),
        (SELECT [budgetCode21] FROM TABLE_NAME),
        (SELECT [budgetCode22] FROM TABLE_NAME),
        (SELECT [budgetCode23] FROM TABLE_NAME),
        (SELECT [budgetCode24] FROM TABLE_NAME),
        (SELECT [budgetCode25] FROM TABLE_NAME),
        (SELECT [budgetCode26] FROM TABLE_NAME),
        (SELECT [budgetCode27] FROM TABLE_NAME),
        (SELECT [budgetCode28] FROM TABLE_NAME),
        (SELECT [budgetCode29] FROM TABLE_NAME),
        (SELECT [budgetCode30] FROM TABLE_NAME) AS BudgetCodes
  FROM TABLE_NAME

Answer 1

您的查询将 return 30 列，如果 TABLE_NAME 有多个记录，将会出错。相反，您想在此处使用 UNION 查询：

    SELECT [budgetCode1] FROM TABLE_NAME
    UNION ALL
    SELECT [budgetCode2] FROM TABLE_NAME
    UNION ALL
    SELECT [budgetCode3] FROM TABLE_NAME
    UNION ALL
    SELECT [budgetCode4] FROM TABLE_NAME
    UNION ALL
    SELECT [budgetCode5] FROM TABLE_NAME
    UNION ALL
    SELECT [budgetCode6] FROM TABLE_NAME
    UNION ALL
    SELECT [budgetCode7] FROM TABLE_NAME
    UNION ALL
    SELECT [budgetCode8] FROM TABLE_NAME
    UNION ALL
    SELECT [budgetCode9] FROM TABLE_NAME
    UNION ALL
    SELECT [budgetCode10] FROM TABLE_NAME
    UNION ALL
    SELECT [budgetCode11] FROM TABLE_NAME
    UNION ALL
    SELECT [budgetCode12] FROM TABLE_NAME
    UNION ALL
    SELECT [budgetCode13] FROM TABLE_NAME
    UNION ALL
    SELECT [budgetCode14] FROM TABLE_NAME
    UNION ALL
    SELECT [budgetCode15] FROM TABLE_NAME
    UNION ALL
    SELECT [budgetCode16] FROM TABLE_NAME
    UNION ALL
    SELECT [budgetCode17] FROM TABLE_NAME
    UNION ALL
    SELECT [budgetCode18] FROM TABLE_NAME
    UNION ALL
    SELECT [budgetCode19] FROM TABLE_NAME
    UNION ALL
    SELECT [budgetCode20] FROM TABLE_NAME
    UNION ALL
    SELECT [budgetCode21] FROM TABLE_NAME
    UNION ALL
    SELECT [budgetCode22] FROM TABLE_NAME
    UNION ALL
    SELECT [budgetCode23] FROM TABLE_NAME
    UNION ALL
    SELECT [budgetCode24] FROM TABLE_NAME
    UNION ALL
    SELECT [budgetCode25] FROM TABLE_NAME
    UNION ALL
    SELECT [budgetCode26] FROM TABLE_NAME
    UNION ALL
    SELECT [budgetCode27] FROM TABLE_NAME
    UNION ALL
    SELECT [budgetCode28] FROM TABLE_NAME
    UNION ALL
    SELECT [budgetCode29] FROM TABLE_NAME
    UNION ALL
    SELECT [budgetCode30] FROM TABLE_NAME

您还可以添加这是从哪个 budgetcode 列中得出的：

    SELECT [budgetCode1],"budgetCode1" as budgetcode FROM TABLE_NAME
    UNION ALL
    SELECT [budgetCode2],"budgetCode2" as budgetcode FROM TABLE_NAME
    UNION ALL
    SELECT [budgetCode3],"budgetCode3" as budgetcode FROM TABLE_NAME
    UNION ALL
    SELECT [budgetCode4],"budgetCode4" as budgetcode FROM TABLE_NAME
    UNION ALL
    SELECT [budgetCode5],"budgetCode5" as budgetcode FROM TABLE_NAME
    UNION ALL
    SELECT [budgetCode6],"budgetCode6" as budgetcode FROM TABLE_NAME
    UNION ALL
    SELECT [budgetCode7],"budgetCode7" as budgetcode FROM TABLE_NAME
    UNION ALL
    SELECT [budgetCode8],"budgetCode8" as budgetcode FROM TABLE_NAME
    UNION ALL
    SELECT [budgetCode9],"budgetCode9" as budgetcode FROM TABLE_NAME
    UNION ALL
    SELECT [budgetCode10],"budgetCode10" as budgetcode FROM TABLE_NAME
    UNION ALL
    SELECT [budgetCode11],"budgetCode11" as budgetcode FROM TABLE_NAME
    UNION ALL
    SELECT [budgetCode12],"budgetCode12" as budgetcode FROM TABLE_NAME
    UNION ALL
    SELECT [budgetCode13],"budgetCode13" as budgetcode FROM TABLE_NAME
    UNION ALL
    SELECT [budgetCode14],"budgetCode14" as budgetcode FROM TABLE_NAME
    UNION ALL
    SELECT [budgetCode15],"budgetCode15" as budgetcode FROM TABLE_NAME
    UNION ALL
    SELECT [budgetCode16],"budgetCode16" as budgetcode FROM TABLE_NAME
    UNION ALL
    SELECT [budgetCode17],"budgetCode17" as budgetcode FROM TABLE_NAME
    UNION ALL
    SELECT [budgetCode18],"budgetCode18" as budgetcode FROM TABLE_NAME
    UNION ALL
    SELECT [budgetCode19],"budgetCode19" as budgetcode FROM TABLE_NAME
    UNION ALL
    SELECT [budgetCode20],"budgetCode20" as budgetcode FROM TABLE_NAME
    UNION ALL
    SELECT [budgetCode21],"budgetCode21" as budgetcode FROM TABLE_NAME
    UNION ALL
    SELECT [budgetCode22],"budgetCode22" as budgetcode FROM TABLE_NAME
    UNION ALL
    SELECT [budgetCode23],"budgetCode23" as budgetcode FROM TABLE_NAME
    UNION ALL
    SELECT [budgetCode24],"budgetCode24" as budgetcode FROM TABLE_NAME
    UNION ALL
    SELECT [budgetCode25],"budgetCode25" as budgetcode FROM TABLE_NAME
    UNION ALL
    SELECT [budgetCode26],"budgetCode26" as budgetcode FROM TABLE_NAME
    UNION ALL
    SELECT [budgetCode27],"budgetCode27" as budgetcode FROM TABLE_NAME
    UNION ALL
    SELECT [budgetCode28],"budgetCode28" as budgetcode FROM TABLE_NAME
    UNION ALL
    SELECT [budgetCode29],"budgetCode29" as budgetcode FROM TABLE_NAME
    UNION ALL
    SELECT [budgetCode30],"budgetCode30" as budgetcode FROM TABLE_NAME AS BudgetCodes
FROM TABLE_NAME

SQL 将多个记录中的值合并到一个列中的查询

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