SQL

Question

我希望调整现有代码以说明两个 datetime 值之间经过的分钟和秒数。我目前提取了过去的时间，但最好不是几个小时，而是 HH:MM:SS 格式，但我似乎找不到任何可以解决我的问题的文档。

Select 
    convert(datetime, Left(Replace(Create_Date, 'T', ' '), 19)) as CreateDate2,
    case 
       when Resolution_date = 'None' then '1999-01-01 12:00:00'
       when Resolution_date <> 'None' then convert(datetime, left(replace(resolution_date, 'T', ' '), 19))
    end as ResolutionDate2,
    datediff(hour, convert(datetime, left(replace(Create_Date, 'T', ' '), 19)), 
    case 
       when Resolution_date = 'None' then '1999-01-01 12:00:00'
       when Resolution_date <> 'None' then convert(datetime, left(replace(Resolution_date, 'T', ' '), 19)) 
    end) as HoursPassed,
    *
from 
    xyz 
where 
    abc;

更具体地说，这部分来自上面的代码：

datediff(hour, convert(datetime,Left(Replace(Create_Date, 'T', ' '), 19)), 
case 
    when Resolution_date = 'None' then '1999-01-01 12:00:00'
    when Resolution_date <> 'None' then convert(datetime, left(replace(Resolution_date, 'T', ' '), 19)) 
end) as HoursPassed

datetime 列最初采用这种格式：

2017-05-25T15:58:26.000+0000

目前的结果是这样的：

2017-05-23 19:51:59.000  2017-05-24 12:38:17.000        17
2017-05-24 15:10:50.000  2017-05-24 16:31:23.000         1
2017-05-25 15:58:26.000  2017-05-25 16:03:30.000         1

Answer 1

您可以将秒数转换为时间。我不会轻易遵循你代码的逻辑，但转换很简单：

select cast(dateadd(second,
                    datediff(second, <starttime>, <enddatime>),
                    0) as time
           )

SQL - datediff returns 小时，但我想在 HH:MM:SS 中添加分钟和秒

SQL - datediff returns hours, but I want to add minutes and seconds in HH:MM:SS

sql-server

datediff

date-difference