解码错误:无法读取数据。阿拉莫菲尔

Error in decoding: The data couldn't be read. Alamofire

我试图通过 JSON 解码器解析 JSON 并使用 Alamofire 获取数据。但是,当我 运行 应用程序时,它显示由于格式不正确而无法读取数据。我尝试了很多东西,但仍然没有用。任何帮助,将不胜感激。来源如下:

VC:

class SecondTaskVC: UIViewController {

var weatherModel = [WeatherModelDecodable]()

override func viewDidLoad() {
    let url = URL(string: "https://api.openweathermap.org/data/2.5/forecast?lat=42.874722&lon=74.612222&APPID=079587841f01c6b277a82c1c7788a6c3")

    Alamofire.request(url!).responseJSON { (response) in

        let result = response.data

        do{
            let decoder = JSONDecoder()
            self.weatherModel = try decoder.decode([WeatherModelDecodable].self, from: result!) // it shows this line as a problem

            for weather in self.weatherModel {
                print(weather.city.name)
            }
        }catch let error{
            print("error in decoding",error.localizedDescription)

        }

    }
     }
   }

数据模型:

struct WeatherModelDecodable: Decodable {
  let city: CityDecodable
}

struct CityDecodable: Decodable {
  let name: String
 }

实际上响应结构与您在这一行尝试做的不同,

self.weatherModel = try decoder.decode([WeatherModelDecodable].self, from: result!)

响应不是数组,您可以在任何浏览器中点击此 Url 在 json viewer 中看到它。您期待一个 json 对象数组,但它不是。所以如果你将它解码为单个对象,它将正确解码如下,

let weatherModel = try decoder.decode(WeatherModelDecodable.self, from: result!)
print(weatherModel.city.name)

所以,SecondTaskVC 看起来像这样,

class SecondTaskVC: UIViewController {

    var weatherModel: WeatherModelDecodable?

    override func viewDidLoad() {
        let url = URL(string: "https://api.openweathermap.org/data/2.5/forecast?lat=42.874722&lon=74.612222&APPID=079587841f01c6b277a82c1c7788a6c3")

        Alamofire.request(url!).responseJSON { (response) in

            let result = response.data

            do{
                let decoder = JSONDecoder()
                self.weatherModel = try decoder.decode(WeatherModelDecodable.self, from: result!)
                print(self.weatherModel!.city.name)
            }catch let error{
                print("error in decoding",error.localizedDescription)

            }

          }
        }
 }

您应该使用您在响应中获得的相同结构来解码相应的对象。