Shell 脚本中基于菜单的选择

Question

我有一个 Shell 脚本可以在一个菜单中完成 4 个任务。到目前为止，我的代码（我猜是基本代码）没有菜单。我希望它在开始时添加菜单，并且我尝试了很多方法（使用 case 语句、if else 和 while 循环）。什么都没有解决。

#!/bin/bash

cd /

echo "1. Basic Details"
echo "2. CPU Information"
echo "3. Network information"
echo "4. All"
echo "5. Cancel"
read option 



if [ $option -eq 1 ];then


    echo ">>>>> Server Name, Date, UPtime <<<<<"
    echo "====================================="
    echo "Date :- `date`"
    echo " "
    echo "Host Name :- `hostname`"
    echo " "
    echo " OS Version"
    oslevel -g
    echo " "
    echo " UPTIME :- "
    uptime
    echo " "
    echo " "

elif [ $option -eq 2 ];then


    echo ">>>>>    CPU and Memory Info.   <<<<<"
    echo "====================================="
    echo " "
    echo 
    echo "          CPU :- `lsdev | grep Processor | wc -l`"
    echo " "
    echo "       Memory :- `lsattr -El mem0 | tail -1`"

    echo " "
    echo " "
    echo "====================================="
    echo ">>>>> Important Kernel Params.  <<<<<"
    echo "====================================="
    echo " "
    echo "****************************************"
    echo " "
    lsattr -El aio0


elif [ $option -eq 3 ];then

    echo ">>>>> Memory Usage Information  <<<<<"

    um=`svmon -G | head -2|tail -1| awk {'print '}`
    um=`expr $um / 256`
    tm=`lsattr -El sys0 -a realmem | awk {'print '}`
    tm=`expr $tm / 1024`
    fm=`expr $tm - $um`
    ump=`expr $um \* 100`
    ump=`expr $ump / $tm`
    echo " "
    echo "Memory Used :- "$ump"%"
    echo " "
    echo "----------------------";
    echo "Memory Information\n";
    echo "total memory = $tm MB"
    echo "free memory = $fm MB"
    echo "used memory = $um MB"
    echo "-----------------------\n";
    echo " "
    echo " "

else
 echo "Enter correct option"
fi

请提出更正建议。没有在脚本中添加选项 4（我需要它来显示所有信息）

Answer 1

这更像是代码审查。

对于菜单，使用 select
使用函数封装功能
将您的代码粘贴到 http://www.shellcheck.net

#!/bin/bash

main() {
    cd /

    PS3="Enter a choice: "
    select ch in "Basic Details" "CPU Information" "Network Information" All Cancel
    do
        case $ch in 
            "Basic Details")
                basicDetails
                ;;
            "CPU Information")
                cpuInfo
                ;;
            "Network Information")
                memUsage            # you need to fix the menu text
                ;;
            All)
                basicDetails
                cpuInfo
                memUsage
                ;;
            Cancel)
                break
                ;;
        esac
    done
}

basicDetails() {
    echo ">>>>> Server Name, Date, UPtime <<<<<"
    echo "====================================="
    echo "Date :- $(date)"
    echo " "
    echo "Host Name :- $(hostname)"
    echo " "
    echo " OS Version"
    oslevel -g
    echo " "
    echo " UPTIME :- "
    uptime
    echo " "
    echo " "
}

cpuInfo() {
    echo ">>>>>    CPU and Memory Info.   <<<<<"
    echo "====================================="
    echo " "
    echo 
    echo "          CPU :- $(lsdev | grep -c Processor)"
    echo " "
    echo "       Memory :- $(lsattr -El mem0 | tail -1)"

    echo " "
    echo " "
    echo "====================================="
    echo ">>>>> Important Kernel Params.  <<<<<"
    echo "====================================="
    echo " "
    echo "****************************************"
    echo " "
    lsattr -El aio0
}

memUsage() {
    echo ">>>>> Memory Usage Information  <<<<<"

    um=$(svmon -G | head -2|tail -1| awk '{print }')
    um=$(( um / 256 ))
    tm=$(lsattr -El sys0 -a realmem | awk '{print }')
    tm=$(( tm / 1024 ))
    fm=$(( tm - um ))
    ump=$(( um * 100 / tm ))
    echo " "
    echo "Memory Used :- $ump%"
    echo " "
    echo "----------------------"
    echo "Memory Information"
    echo
    echo "total memory = $tm MB"
    echo "free memory = $fm MB"
    echo "used memory = $um MB"
    echo "-----------------------"
    echo
    echo " "
    echo " "
}

main "$@"

Answer 2

我很不明白"add the menu at start"，在你的脚本中，菜单是最先打印出来的语句。这是重复菜单的示例，其中退出程序取决于用户输入

#!/bin/sh
#method to just print your menu
printmenu() {
   echo "1. Operation 1"
   echo "2. Operation 2"
   echo "3. Exit"
}

operation1() {
   echo "Operation 1 is performed..!"
}

operation2() {
   echo "Operation 2 is performed..!"
}

while [ 1 ]
do
   printmenu # printing menu
   read u_option

  #case handling the user inputs
  case $u_option in
     1) operation1;; # calling function for operation1
     2) operation2;; # calling function for operation2
     3) echo "Terminating the program as per your request"
        exit;;
     *) echo "Invalid option, provide only valid integers"
   esac
done

Answer 3

bash 具有 select 内置：

select val in cherry banana apple ;  do
    echo "$val"
    # do other things with $val
    # ...
    break # Leave this out if you want to run
          # the menu forever in an endless loop
done

Shell 脚本中基于菜单的选择

Menu based selection in Shell scripting

linux

shell

unix

sh

aix