如何更新布尔类型列 - Laravel 5.5

how to update Boolean type column - Laravel 5.5

我的数据库中有一个用于图像缩略图的布尔列。一个选定的行将是缩略图(并且将具有值 1),而其他行将是 0。如何将选定的行值更新为 1 和其他 0.

当我运行这个更新函数时,它每次都会根据ID更新行。

public function update(Request $request, $id)
{
    $id = (int) $id;

    $image = HotelGallery::where('id', $id)
                            ->update(['is_thumbnail' => '1']);

    return response()->json(['success' => 'Done']);
}

ID 23 具有值 1,我如何根据 [= 更新此 is_thumbnail 行32=]ID 即 3,将是 1 而其他 is_thumbnail 行应该是 0一个查询?

//To Update row two as shown in above image 
query="UPDATE $data_base_name.$data_base_table SET `is_thumbnail`=0 WHERE `id`=2";
result=mysqli_query($conn,(query));

//To Update row two as shown in above image (being more specific)
query="UPDATE $data_base_name.$data_base_table SET `is_thumbnail`=false WHERE `id`=2";
result=mysqli_query($conn,(query));

上面的代码会将第二行 is_thumbail 的值更改为 0,因为 1 将上面代码中的 'false' 或 '0' 更改为 '1' 或 'true'。

//Update to improved question (updating all rows)
query="
UPDATE $data_base_name.$data_base_table SET `is_thumbnail`=true WHERE `id`=2;
UPDATE $data_base_name.$data_base_table SET `is_thumbnail`=false WHERE `id`!=2;";
result=mysqli_multi_query($conn,(query));
while (mysqli_next_result($conn)){;}//this is to free result set for multi query

上述查询会将第二行设置为 'true' 或“1”,每隔一行设置为 'false' 或“0”。

如果您是 php 的新手,请阅读 SQL 注射!!!另见 https://secure.php.net/manual/en/mysqli.multi-query.php

//Update to improved question (eloquent format)
Table::where('id', '=',2 )->update(['is_thumbnail' => 'true']);  
Table::where('id', '!=',2 )->update(['is_thumbnail' => 'false']);

这不是在 laravel 中执行此操作的最佳方法,但目前应该可行。

您可以在 PDO or Mysqli 中使用多个查询。

PDO 示例:

$db = new PDO("mysql:host=localhost;dbname=test", 'root', '');

// works regardless of statements emulation
$db->setAttribute(PDO::ATTR_EMULATE_PREPARES, 0);


$thumbnail_id = 2;

$sql = 'UPDATE tab SET tab.is_thumbnail = false;' . "\n" .
       'UPDATE tab SET tab.is_thumbnail = true WHERE tab.id = ?';
try {
    $stmt = $db->prepare($sql);
    $stmt->execute([$thumbnail_id]);
}
catch (PDOException $e)
{
    echo $e->getMessage();
    die();
}

我明白你想要 hotel_id 只有 is_thumbnail=1:

public function update(Request $request, $id)
{
    $id = (int) $id;

    $hotelGallery = HotelGallery::where('id', $id)
                            ->pluck('hotel_id')->toArray();
    $hotel_id = array_get($hotelGallery, '0', 0);
    // Set is_thumbnail = 0 for all image of hotel_id
    HotelGallery::where('hotel_id', $hotel_id)
                        ->update(['is_thumbnail' => 0]);

    $image = HotelGallery::where('id', $id)->update(['is_thumbnail' => 1]);

    return response()->json(['success' => 'Done']);
}

最好的Laravel方法是将此功能集成到模型中:

class HotelGallery extends Model
{
  protected static function boot ()
    {
        parent::boot();

        self::saving(function($model) {
            if($model->attributes['is_thumbnail'] == 1)
            {
                (new self)->where('hotel_id', $model->attributes['hotel_id'])->where('id', '<>', $model->attributes['id'] ?? 0)->update(['is_thumbnail' => 0]);
            }
        });
    }
}