Python - 使用 concurrent.futures 阅读地图
Python - Read a map with concurrent.futures
为了减少我的计算时间,在post之后,有人告诉我用concurrent.futures映射。但是我看不到结果,我得到 "generator object map at 0x7f0ef48ff2d0>"...我该怎么做?
import concurrent.futures
import numpy
def f(num):
return num * 2
arr = numpy.array(
[numpy.array([
numpy.array([1,2,3]),
numpy.array([4,5,6]),
numpy.array([7,8,9])]),
numpy.array([
numpy.array([1,2,3]),
numpy.array([4,5,6]),
numpy.array([7,8,9])])])
with concurrent.futures.ProcessPoolExecutor() as exc:
print(exc.map(f, arr))
调用map
return是一个迭代器,它不会return直接产生结果。您可以执行以下操作:
with concurrent.futures.ProcessPoolExecutor() as exc:
for result in exc.map(f, arr):
print(result)
为了减少我的计算时间,在post之后,有人告诉我用concurrent.futures映射。但是我看不到结果,我得到 "generator object map at 0x7f0ef48ff2d0>"...我该怎么做?
import concurrent.futures
import numpy
def f(num):
return num * 2
arr = numpy.array(
[numpy.array([
numpy.array([1,2,3]),
numpy.array([4,5,6]),
numpy.array([7,8,9])]),
numpy.array([
numpy.array([1,2,3]),
numpy.array([4,5,6]),
numpy.array([7,8,9])])])
with concurrent.futures.ProcessPoolExecutor() as exc:
print(exc.map(f, arr))
调用map
return是一个迭代器,它不会return直接产生结果。您可以执行以下操作:
with concurrent.futures.ProcessPoolExecutor() as exc:
for result in exc.map(f, arr):
print(result)