Django FormView 在 success_url 中传递 pk

Question

假设我有以下 FormView，并且我想在提交表单后将 item.pk 传递给其他视图。我想我必须编辑 get_success_url() 但我什至不知道如何从 form_valid():

得到 item.pk

models.py

from django.db import models

class Book(models.Model):
    field1 = models.CharField(max_length=32)
    field2 = models.CharField(max_length=32)
    field3 = models.CharField(max_length=32)

    def __str__(self):
        return self.field1

forms.py

from django import forms
from .models import Book

class SomeForm(forms.ModelForm):

    field_order = ['field3', 'field2', 'field1']

    class Meta:
        model = Book
        fields = ['field1', 'field2', 'field3']

views.py

from django.shortcuts import render
from django.views.generic.edit import FormView
from .forms import SomeForm

class SomeView(FormView):
    form_class = SomeForm
    template_name = 'appname/form.html'
    success_url = reverse_lazy('somewhere')


    def form_valid(self, form):

        # save in Database
        item = form.save()

        # item.pk stores the saved pk 

        return super().form_valid(form)

    def get_success_url(self)
         # how can i get item.pk from form_valid() here and pass it to another view?

Answer 1

你可以像下面那样做

class SomeView(FormView):
    form_class = SomeForm
    template_name = 'appname/form.html'
    success_url = reverse_lazy('somewhere')
    pk = None


    def form_valid(self, form):
        item = form.save()
        self.pk = item.pk
        return super(SomeView, self).form_valid(form)

    def get_success_url(self):
         #print(self.pk)
         return reverse('some_url', kwargs={'pk': self.pk})

Answer 2

我发现了一些非常直接的东西：

views.py

class SomeView(FormView):
    ...
    context_object_name = 'object_name'
    ...

    def get_success_url(self)
        return reverse('some_url', kwargs={'pk': self.get_context_data()['object_name'].pk})

Django FormView 在 success_url 中传递 pk

Django FormView pass pk in success_url

django

django-forms

django-views

django-class-based-views