Python 3 中 LogonUserW 中的访问冲突

Access Violation in LogonUserW in Python 3

我正在为某人编写一个 Python3 脚本,它通过 ctypes 使用 advapi dll 及其 LogonUserW 函数。

当运行代码

__init__函数中

dll_location = find_library("advapi32");

if (dll_location == None):
    raise FileNotFoundError

adv_dll = WinDLL(dll_location);

#gets the pointer to the function
logonUser = adv_dll.LogonUserW;
self.logonUser = logonUser

在登录(用户名、域、密码)函数中

#Sets the parameters to call the DLL
loginType = DWORD(2)
loginProvider = DWORD(0)
handle = PHANDLE()
user = LPCSTR(username.encode());
pw = LPCSTR(password.encode());
dom = LPCSTR(domain.encode());

rescode = self.logonUser(user, dom, pw, loginType, loginProvider, handle);

提高OSError: exception: access violation writing 0x0000000000000000

知道可能导致错误的原因以及如何解决吗?

PS:是的,我知道我没有遵循 PEP 8 的变量名,我通常是 java 程序员。

根据[Python]: types - A foreign function library for Python, you should set argtypes and restype (this is one way) for the function you're calling ([MS.Docs]: LogonUserW function).

下面是调用它的最小示例。但是,如果您需要调用多个这样的函数,您还可以考虑 [GitHub]: Python for Windows (pywin32) Extensions,这是 PythonWINAPI[=44 的包装=]s.

code.py:

import sys
import ctypes
from ctypes import wintypes


def main():
    advapi32_dll = ctypes.WinDLL("advapi32.dll")
    logon_user_func = advapi32_dll.LogonUserW
    logon_user_func.argtypes = [wintypes.LPCWSTR, wintypes.LPCWSTR, wintypes.LPCWSTR, wintypes.DWORD, wintypes.DWORD, wintypes.PHANDLE]
    logon_user_func.restype = wintypes.BOOL

    user = "dummy_user"
    domain = "dummy_domain"
    pwd = "dummy_pwd"
    logon_type = 2
    provider = 0
    handle = wintypes.HANDLE()
    ret = logon_user_func(user, domain, pwd, logon_type, provider, ctypes.byref(handle))
    print("{:s} returned {:}".format(logon_user_func.__name__, "TRUE" if ret else "FALSE"))


if __name__ == "__main__":
    print("Python {:s} on {:s}\n".format(sys.version, sys.platform))
    main()

备注:

  • 除了argtypes / restypes
    • Python3中字符串默认是,所以不需要encode()
    • HANDLE 通过 byref
    • 传递

输出:

(py35x64_test) e:\Work\Dev\Whosebug\q051251086>"e:\Work\Dev\VEnvs\py35x64_test\Scripts\python.exe" code.py
Python 3.5.4 (v3.5.4:3f56838, Aug  8 2017, 02:17:05) [MSC v.1900 64 bit (AMD64)] on win32

LogonUserW returned FALSE