将数据合并为 1 行

Question

初始数据示例：

 Project   |   Modified   | LastModify |
 ---------------------------------------
 Project 1 |  12.01.2018  |      3     |
 Project 2 |  10.02.2017  |      2     |
 Project 1 |  15.01.2018  |      2     |
 Project 1 |  18.01.2018  |      1     |
 Project 2 |  15.02.2017  |      1     |

我通过查询得到了这个结果：

SELECT *
, Row_number() over (partition by Project order by Modified desc ) as LastModify
FROM Table_A

我需要为第 Lastmodify = 1

列的行添加带有首次修改项目日期的列

即为每个 Project 获取 1 行，第一个修改日期和最后一个修改日期

预期结果如下：

 Project   |   Modified   | LastModify | FirstModifyDate|
 ----------------------------------------------------
 Project 1 |  18.01.2018  |      1     |  12.01.2018   |
 Project 2 |  15.02.2017  |      1     |  10.02.2017   |

我该怎么做？

Answer 1

如果您的 Sql 服务器版本等于或高于 2012，这将有效：

SELECT *
, Row_number() over (partition by Project order by Modified desc ) as LastModify
, First_value(Modified) over (partition by Project order by Modified asc) [FirstModifyDate]
FROM Table_A

Answer 2

我创建了一个与您的数据相似的 table 并应用了可能有帮助的查询。 you can refer to this image

SELECT new.project
    ,new.times
    ,new.pdate
    ,sec.p1date
FROM new
INNER JOIN (
    SELECT child.project AS p
        ,child.pdate AS p1date
    FROM new AS child
    INNER JOIN new ON child.project = new.project
    GROUP BY child.project
    HAVING child.times = MAX(child.times)
    ) AS sec ON sec.p = new.project
WHERE new.times = 1

将数据合并为 1 行

Combine data in 1 row

sql

sql-server

sql-server-2017