SQL 中的字符串排序

Question

大家好我有这个 SQL 查询，我的查询越来越好，但我仍然不擅长解析数据以使其看起来像你想要的那样。

SELECT r.queueName, COUNT(*) as qty FROM LeaseComplete.dbo.QueueEntries q
    INNER JOIN LeaseComplete.dbo.Queues r
        ON r.queueID = q.queueentryQueueID
    LEFT JOIN LeaseComplete.dbo.QueueActions a 
        ON a.queueactQueueEntryID = q.queueentryID
        AND a.queueactCreationDate >(CONVERT(datetime, GETDATE()) -1)
    WHERE q.queueentryAddDate > (CONVERT(datetime, GETDATE()) -1) 
    AND q.queueentryTaskTypeCode = 'Collection'
    AND q.queueentryStatus != 'Closed'
    AND r.queueTypeCode = 'Collection'
    AND r.queueTypeCode = 'Mileage'
    AND r.queueTypeCode = 'Insurance'
    AND r.queueName NOT LIKE '%referral%'
    OR r.queueName LIKE '%Awhite%'
    OR r.queueName LIKE '%Dsmith%'
    OR r.queueName LIKE '%Kmartin%'
    OR r.queueName LIKE '%Mgonzalez%'
    OR r.queueName LIKE '%Ckponton%'
    OR r.queueName LIKE '%WTamayo%'
    OR r.queueName LIKE '%mbare%'
    OR r.queueName LIKE '%dlittle%'

    GROUP BY r.queueName

所以我有上面的查询，它应该提取任何数据，其中包含 queueName 列的首字母、姓氏，如果它还包含里程、保险和收款。所以我得到了下面的数据集。

+--------------------------------+-----+
|           queueName            | qty |
+--------------------------------+-----+
| Collection AWhite Delinquent   | 494 |
| Collection AWhite Followup     |  10 |
| Collection AWhite Legal        |   9 |
| Collection CKponton Delinquent | 790 |
| Collection CKponton Followup   |  38 |
| Collection CKponton Mileage    |   2 |
| Collection DLittle Delinquent  | 114 |
| Collection DLittle Legal       |  28 |
| Collection DSmith Delinquent   | 486 |
| Collection DSmith Followup     |  21 |
| Collection DSmith Legal        |  56 |
| Collection KMartin Delinquent  |  97 |
| Collection KMartin Followup    |   3 |
| Collection MBare Delinquent    | 773 |
| Collection MBare Followup      |  22 |
| Collection MBare Legal         |   1 |
| Collection MBare Mileage       |  44 |
| Collection MGonzalez Delinquen | 739 |
| Collection MGonzalez Followup  |  31 |
| Collection Referral DSmith     | 107 |
| Collection WTamayo Delinquent  | 682 |
| Collection WTamayo Followup    |  21 |
| Collection WTamayo Mileage     |   1 |
| Insurance Collection AWhite    |  44 |
| Insurance Collection CKponton  |  59 |
| Insurance Collection DLittle   |  17 |
| Insurance Collection DSmith    |  46 |
| Insurance Collection KMartin   |   2 |
| Insurance Collection MBare     |  40 |
| Insurance Collection MGonzalez |  35 |
| Insurance Collection WTamayo   |  50 |
| Insurance Monitor AWhite       |   2 |
| Insurance Monitor CKponton     |   2 |
| Insurance Monitor MBare        |   1 |
| Insurance Monitor MGonzalez    |   3 |
| Insurance Monitor WTamayo      |   2 |
+--------------------------------+-----+

如您所见，它仍然至少拉动列中的 'Referral' 一次，这不是我想要的。我也在尝试弄清楚如何制作它，这样它也不会显示 Insurance Monitor 列。如何以正确的方式让这些字符串名称优先于彼此。对不起，如果我的语法很糟糕，我今天还在醒来。

Answer 1

你的查询是敬酒：你混合了 AND 和 OR 条件，没有任何 () 来强制执行 parse/execution 命令，并且你有不可能的条件:

AND r.queueTypeCode = 'Collection'
AND r.queueTypeCode = 'Mileage'

单个 field/value 不可能同时具有多个不同的值。你基本上是在说 "This field must be a banana and a submarine simultaneously".

还有：http://dev.mysql.com/doc/refman/5.0/en/operator-precedence.html 请注意 AND 的优先级高于 OR。

Answer 2

我猜你想要这样的东西

SELECT r.queueName, COUNT(*) as qty FROM LeaseComplete.dbo.QueueEntries q
    INNER JOIN LeaseComplete.dbo.Queues r
        ON r.queueID = q.queueentryQueueID
    LEFT JOIN LeaseComplete.dbo.QueueActions a 
        ON a.queueactQueueEntryID = q.queueentryID
        AND a.queueactCreationDate >(CONVERT(datetime, GETDATE()) -1)
    WHERE (q.queueentryAddDate > (CONVERT(datetime, GETDATE()) -1) 
    AND q.queueentryTaskTypeCode = 'Collection'
    AND q.queueentryStatus != 'Closed'
    AND r.queueTypeCode IN ('Collection', 'Mileage', 'Insurance')
    AND r.queueName NOT LIKE '%referral%')
    AND( r.queueName LIKE '%Awhite%'
    OR r.queueName LIKE '%Dsmith%'
    OR r.queueName LIKE '%Kmartin%'
    OR r.queueName LIKE '%Mgonzalez%'
    OR r.queueName LIKE '%Ckponton%'
    OR r.queueName LIKE '%WTamayo%'
    OR r.queueName LIKE '%mbare%'
    OR r.queueName LIKE '%dlittle%')

    GROUP BY r.queueName
    ORDER BY r.queueName

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