运行 每 X 秒编码一次

run code every X seconds

我有从串口读取字节的无限循环,我想每隔 X 秒将读取的数据保存到 firebase 数据库。

我使用了这段代码,但没有用:

import threading

def printit():
  threading.Timer(5.0, printit).start()
  print "Hello, World!"

printit()

这是我的代码

import serial

ser = serial.Serial()
ser.baudrate = 115200
ser.port = "/dev/ttyUSB0"
ser.timeout = 30
try:
    try:
        while 1:
            line = ser.readline().rstrip().decode('utf-8')

            # print("save data here every X seconds)
    except KeyboardInterrupt:
        ser.close()  # Close port
        pass
except serial.serialutil.SerialException as e:
    print(str(e))

我不能使用睡眠,因为它阻塞了主线程,那么如何让代码连续读取并每隔 X 秒打印 "data saved"(我将保存到数据库中)

希望我没有正确理解您的意思。使用time.time()设置定时器。

import time

def doEvery_X_Seconds():
        print("I do it every X seconds")
        time.sleep(1)

TIMER_LIMIT = 5
setTimer = time.time()

while(1):

        print("hello world")
        if(time.time() - setTimer >= TIMER_LIMIT):
                doEvery_X_Seconds()
                setTimer = time.time()

time.sleep(1) 只是为了证明它有效。

感谢Lutz Horn在评论中的建议,我是这样解决问题的:

import schedule
import time
import serial

ser = serial.Serial()
ser.baudrate = 115200
ser.port = "/dev/ttyUSB0"
ser.timeout = 30

schedule.every(10).seconds.do(save_db)
try:
    try:
        while 1:
            schedule.run_pending()
            line = ser.readline().rstrip().decode('utf-8')
            # here every 10 seconds the function save_db will be called 
    except KeyboardInterrupt:
        ser.close()  # Close port
        pass
except serial.serialutil.SerialException as e:
    print(str(e))