Select2 - Ajax 数据 - 根据查询填充下拉列表
Select2 - Ajax Data - Populate The Dropdown based on query
我正在使用 Select2 来填充英国城镇的下拉列表。由于英国城镇数据库非常庞大,我认为 AJAX 调用是引入数据的最佳方式。
我构建了一个 post 函数和一些 PHP(在 Codeigniter 中)来捕获查询并解析它。
我可以看到数据正在 post 编辑和响应,但是我的 Select2 没有填充数据。
我的 jQuery 是:
$("#areas").select2(
{
tags: [],
ajax: {
url: '/profile/get-towns',
dataType: 'json',
type: "POST",
quietMillis: 100,
data: function (term) {
return {
query: term
};
},
results: function (data) {
return {
results: data.town_id
}
},
cache: true
},
escapeMarkup: function (markup) { return markup; }, // let our custom formatter work
minimumInputLength: 4,
placeholder : "Start typing your Town / City",
maximumSelectionSize: 2
}
);
我的回复jSON(例子)如下:
[{"town_id":"16994","town":"Hartle"},{"town_id":"16995","town":"Hartlebury"},{"town_id":"16996","town"
:"Hartlebury"},{"town_id":"16997","town":"Hartlebury Common"},{"town_id":"16998","town":"Hartlepool"
},{"town_id":"16999","town":"Hartley"},{"town_id":"17000","town":"Hartley"},{"town_id":"17001","town"
:"Hartley"},{"town_id":"17002","town":"Hartley"},{"town_id":"17003","town":"Hartley Green"},{"town_id"
:"17004","town":"Hartley Green"},{"town_id":"17005","town":"Hartley Mauditt"},{"town_id":"17006","town"
:"Hartley Wespall"},{"town_id":"17007","town":"Hartley Wintney"},{"town_id":"27051","town":"New Hartley"
},{"town_id":"35891","town":"Stowe-by-Chartley"}]
我哪里错了?理想情况下,我希望 select 下拉菜单的 select 值 = town_id 和 select 选项是城镇名称。
谢谢。
在您的 ajax 呼叫中,尝试添加 success。像这样:
success: function( json ) {
$.each(items, function (i, item) {
$('#mySelect').append($('<option>', {
value: item.value,
text : item.text
}));
)};
}
在您的 select2
配置中:
results: function (data) {
var res = [];
for(var i = 0 ; i < data.length; i++) {
res.push({id:data[i].town_id, text:data[i].town});
}
return {
results: res
}
},
因为 select2
想要结果作为具有键 id
和 text
.
的对象数组
否则你已经可以returns一个结构良好的对象
[
{"id":"16994","text":"Hartle"},
{"id":"16995","text":"Hartlebury"},
{"id":"16996","text":"Hartlebury"},
{"id":"16997","text":"Hartlebury Common"}
]
然后
results: function (data) {
return {
results: data
}
},
我正在使用 Select2 来填充英国城镇的下拉列表。由于英国城镇数据库非常庞大,我认为 AJAX 调用是引入数据的最佳方式。
我构建了一个 post 函数和一些 PHP(在 Codeigniter 中)来捕获查询并解析它。
我可以看到数据正在 post 编辑和响应,但是我的 Select2 没有填充数据。
我的 jQuery 是:
$("#areas").select2(
{
tags: [],
ajax: {
url: '/profile/get-towns',
dataType: 'json',
type: "POST",
quietMillis: 100,
data: function (term) {
return {
query: term
};
},
results: function (data) {
return {
results: data.town_id
}
},
cache: true
},
escapeMarkup: function (markup) { return markup; }, // let our custom formatter work
minimumInputLength: 4,
placeholder : "Start typing your Town / City",
maximumSelectionSize: 2
}
);
我的回复jSON(例子)如下:
[{"town_id":"16994","town":"Hartle"},{"town_id":"16995","town":"Hartlebury"},{"town_id":"16996","town"
:"Hartlebury"},{"town_id":"16997","town":"Hartlebury Common"},{"town_id":"16998","town":"Hartlepool"
},{"town_id":"16999","town":"Hartley"},{"town_id":"17000","town":"Hartley"},{"town_id":"17001","town"
:"Hartley"},{"town_id":"17002","town":"Hartley"},{"town_id":"17003","town":"Hartley Green"},{"town_id"
:"17004","town":"Hartley Green"},{"town_id":"17005","town":"Hartley Mauditt"},{"town_id":"17006","town"
:"Hartley Wespall"},{"town_id":"17007","town":"Hartley Wintney"},{"town_id":"27051","town":"New Hartley"
},{"town_id":"35891","town":"Stowe-by-Chartley"}]
我哪里错了?理想情况下,我希望 select 下拉菜单的 select 值 = town_id 和 select 选项是城镇名称。
谢谢。
在您的 ajax 呼叫中,尝试添加 success。像这样:
success: function( json ) {
$.each(items, function (i, item) {
$('#mySelect').append($('<option>', {
value: item.value,
text : item.text
}));
)};
}
在您的 select2
配置中:
results: function (data) {
var res = [];
for(var i = 0 ; i < data.length; i++) {
res.push({id:data[i].town_id, text:data[i].town});
}
return {
results: res
}
},
因为 select2
想要结果作为具有键 id
和 text
.
否则你已经可以returns一个结构良好的对象
[
{"id":"16994","text":"Hartle"},
{"id":"16995","text":"Hartlebury"},
{"id":"16996","text":"Hartlebury"},
{"id":"16997","text":"Hartlebury Common"}
]
然后
results: function (data) {
return {
results: data
}
},